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UkoKoshka [18]
3 years ago
7

Basma cuts ribbon to its onto balloons for the carnival. She has 925.6 inches of ribbon in all. If each ribbon must be 24 inches

long, how many ribbons can she cut? For the remainder in this problem you should: ignore it, round up, form a fraction with it.
Mathematics
1 answer:
dlinn [17]3 years ago
8 0

Answer:

Basma can cut 38 ribbons.

For the remainder in this problem we should <u>ignore it</u>.

Step-by-step explanation:

Given:

Length of the ribbon she has in all = 925.6 in

Length of each ribbon = 24 in.

We need to find the number of ribbons she can cut.

Solution:

Now we know that;

number of ribbons she can cut can be calculated by dividing Length of the ribbon she has in all by Length of each ribbon.

framing in equation form we get;

number of ribbons she can cut = \frac{925.6}{24} = 38.57

so we can say that;

Basma can cut 38 ribbons.

For the remainder in this problem we should <u>ignore it</u>.

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Step-by-step explanation:


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3 years ago
A room has three lightbulbs. Each one has a 30% probability of burning out within the month. Write the probability as a percenta
lesantik [10]

Answer:

97.3%

Step-by-step explanation:

Let the three bulbs be A, B and C respectively.

Let P(A) denote the probability that the first bulb will burn out

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Let P(C) denote the probability that the third bulb will burn out

Now, we are told that Each one has a 30% probability of burning out within the month.

Thus;

P(A) = P(B) = P(C) = 30% = 0.3

Now, probability that at the end of the month at least one of the bulbs will be lit will be given as;

P(at least one bulb will be lit) = 1 - (P(A) × P(B) × P(C))

P(at least one bulb will be lit) = 1 - (0.3 × 0.3 × 0.3) = 0.973 = 97.3%

3 0
3 years ago
Can anyone rewrite the quadratic function in standard form?
ycow [4]

Answer:

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3 years ago
What is 8.517 in expanded form
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5 0
3 years ago
A ball is thrown into the air from a height of 9cm above the ground, and its height is given by S=128+32t-16t^2, where t is the
OverLord2011 [107]
-16t² + 32t + 128 = 0
-16t² + 64t - 32t + 128 = 0
-16t(t - 4) - 32(t - 4)
(-16t - 32)(t - 4) = 0
-16t -32 = 0      t - 4 = 0
-16t = 32          t = 4
t = -2

t = -2 and t = 4 are the values that makes S = 0.
Yes, because if you apply either of  these values alone, S will be 0.
6 0
3 years ago
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