Y=7 because there is no slope and the Y intercept is at 7.
Answer:
100 yds^2
Step-by-step explanation:
To find the area of a square, we need to know the length of one side of the square. Since the perimeter is 4 times the length of one side, or 4s, and since 4s = 40 yds, s must be 10 yds.
Then the area of the square is (10 yds)^2 = 100 yds^2.
Answer:
We know that ,
So ,
we can add 2 pi to it since there will be no change in the value
Also,
Answer : Option B
width = x
length = 2x+8
area = l x w
x<span>(2x+8)</span>=120
<span><span>2<span>x^2</span>+8x−120=0 </span>
</span>
<span><span><span>x^2</span>+4−60=0 </span></span>
<span><span><span>(x+10)</span><span>(x−6)</span>=0</span>
</span>
<span><span>x=−10 and x=6 </span></span>
<span><span> width has to be a positive number</span></span>
Width = <span>6
</span> inches.
Answer:
Step-by-step explanation:
Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.
Problem 1:
(x²)/4 +y²= 1
y= x+1
*substitute for y*
Now we have a one-variable equation we can solve-
x²/4 + (x+1)² = 1
x²/4 + (x+1)(x+1)= 1
x²/4 + x²+2x+1= 1
*subtract 1 from both sides to set equal to 0*
x²/4 +x^2+2x=0
x²/4 can also be 1/4 * x²
1/4 * x² +1*x² +2x = 0
*combine like terms*
5/4 * x^2+2x+ 0 =0
now, you can use the quadratic equation to solve for x
a= 5/4
b= 2
c=0
the syntax on this will be rough, but I'll do my best...
x= (-b ± √(b²-4ac))/(2a)
x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))
x= (-2 ±√(4-0))/(2.5)
x= (-2±2)/2.5
x will have 2 answers because of ±
x= 0 or x= 1.6
now plug that back into one of the equations and solve.
y= 0+1 = 1
y= 1.6+1= 2.6
Hopefully this explanation was enough to help you solve problem 2.
Problem 2:
x² + y² -16y +39= 0
y²- x² -9= 0
