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Maurinko [17]
3 years ago
9

If 2d = 5c, then all of the following are true except _____.

Mathematics
2 answers:
Bad White [126]3 years ago
4 0
D is the only one not true
natali 33 [55]3 years ago
3 0

Answer:

\frac{2}{d} = \frac{5}{c}

Option d is correct

Step-by-step explanation:

Given that:

2d = 5c

Option d.

\frac{2}{5} = \frac{c}{d}

By cross multiply we have;

2d = 5c  which is true.

Option b.

\frac{5}{2} = \frac{d}{c}

By cross multiply we have;

5c =2d  which is true.

Option c.

\frac{2}{c} = \frac{5}{d}

By cross multiply we have;

5d =5c  which is true.

Option d.

\frac{2}{d} = \frac{5}{c}

By cross multiply we have;

2c = 5d

which is not true.

Therefore, all of the following are true except \frac{2}{d} = \frac{5}{c}

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Two 5-year girls, Alyse and Jocelyn, have been training to run a 1-mile race. Alyse's 1 mile time A is approximately Normally di
tatyana61 [14]

Answer:

1.7 × 10⁻⁴

Step-by-step explanation:

The question relates to a two sample z-test for the comparison between the means of the two samples  

The null hypothesis is H₀:  μ₁ ≤ μ₂

The alternative hypothesis is Hₐ: μ₁ > μ₂

z=\dfrac{(\bar{x}_1-\bar{x}_2)-(\mu_{1}-\mu _{2} )}{\sqrt{\dfrac{\sigma_{1}^{2} }{n_{1}}-\dfrac{\sigma _{2}^{2}}{n_{2}}}}

Where;

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σ₁ = 2.5

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We set our α level at 0.05

Therefore, our critical z = ± 1.96

For n₁ = n₂ = 23, we have;

z=\dfrac{(13.5-12)-(0)}{\sqrt{\dfrac{2.5^{2} }{23}-\dfrac{1.5^{2}}{23}}} = 3.5969

We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96

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Therefore;

The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.

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Answer:

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