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4 years ago

What times what equals 43

Mathematics

2 answers:

myrzilka [38]4 years ago

5 0

I believe your answer would be 2 x 21.5 = 43 :D

Nimfa-mama [501]4 years ago

3 0

1 times 43 equals 43.

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B the numerous in x the column increase

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3 years ago

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Given that f(x) = 10x + 45, find f(0)

Sergeeva-Olga [200]

Awnser : 45

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2 years ago

A student designed this sculpture. Using the dimensions on the sculpture, find the dimensions of each rectangular prism. Then ca

jolli1 [7]

Answer:

Prism Y

$Height = 12in$

$Length = 6in$

$Width = 4in$

$Volume = 288in^3$

Prism Z

$Height = 18in$

$Length =10in$

$Width = 10in$

$Volume = 1800in^3$

$Total = 2088in^3$

Step-by-step explanation:

Given

See attachment for sculpture

Solving (a) The dimension and volume of Y

From the attachment

$Height = 18 - 6$

18 in is the height of Z and 6in represents the length (height) of the unoccupied space by Y

So:

$Height = 12in$

$Length = 16 - 10$

16 in is the total length of the sculpture and 10 in represents the length of Z

So:

$Length = 6in$

$Width = 10 - 6$

10 in is the width of Z and 6in represents the length (width) of the unoccupied space by Y

So:

$Width = 4in$

Hence, the dimension of Y is:

$Height = 12in$

$Length = 6in$

$Width = 4in$

Volume is then calculated as:

$Volume = Length * Width * Height$

$Volume = 12in * 6in * 4in$

$Volume = 288in^3$

Solving (b) The dimension and volume of Z

As identified in (a), the dimensions of Z are:

$Height = 18in$

$Length =10in$

$Width = 10in$

Volume is then calculated as:

$Volume = Length * Width * Height$

$Volume = 18in * 10in * 10in$

$Volume = 1800in^3$

Solving (c): Total volume of the sculpture.

To do this, we simply add up the volumes of Y and Z.

So, we have:

$Total = 288in^3 + 1800in^3$

$Total = 2088in^3$

6 0

3 years ago

Lina is packing to move to a new house. She has 561 items to transfer to the new house. 36 of the items are large items that wil

Lyrx [107]

Answer: See explanation

Step-by-step explanation:

Your question isn't complete but let me give different scenarios to help you solve.

Firstly, assuming we want to calculate the amount of items left after the large items are carried alone, this will be:

= 561 - 36

= 525

Secondly, if we want to know the percentage of the large items that will be carried alone. This will be:

= 36/561 × 100.

= 6.42%

Thirdly, if you want to know the percentage of the items that will be left after the large ones have been carried alone. This will be:

= 100% - 6.42%

= 93.58%

5 0

3 years ago

There are ten balls in a bag. Three balls are black and seven balls are white. a One ball is chosen at random and then replaced.

pickupchik [31]

Answer:

Given:

Total balls = 10
Black balls = 3
White balls = 7

⇒ P(black ball) = 3/10 = 0.3

⇒ P(white ball) = 7/10 = 0.7

If one ball is chosen at random and <u>replaced</u>, the probabilities do not change between the first and second ball.

Let event D = first ball is black

Let event S = second ball is black

P(D) = 0.3

P(S) = 0.3 (since the first ball is replaced)

⇒ P(D ∩ S) = P(D) × P(S)

= 0.3 × 0.3

= 0.09

For Independent Events we know that: P(A ∩ B) = P(A) × P(B)

Therefore, as P(D ∩ S) = P(D) × P(S) the events are independent.

3 0

2 years ago