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Aleksandr [31]
3 years ago
8

Simplify this expression. 6^7 ÷ 6^5 A. 30 B. 35 C. 36 D. 42

Mathematics
2 answers:
bulgar [2K]3 years ago
6 0

Answer:

C 36

Step-by-step explanation:

When we have to exponents to the same base, and we are dividing them, we can subtract the exponents

a^b ÷ a^c = a^ (b-c)

6^7 ÷ 6^5 = 6^(7-5)

                 = 6^(2)

                = 36

Dima020 [189]3 years ago
3 0

ANSWER

C. 36

EXPLANATION

The given expression is

{6}^{7}  \div  {6}^{5}

Recall that,

{a}^{m}   \div  {a}^{n}  =  {a}^{ m - n}

We apply this property to get,

{6}^{7}\div  {6}^{5}  =  {6}^{7 - 5}

This will give us,

{6}^{7}\div  {6}^{5}  =  {6}^{2}

{6}^{7}\div  {6}^{5}= 36

The correct choice is C.

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what quadrilateral has exactly two pairs of consecutive angles that are supplementary and none of the opposite angles are congru
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Answer:

If a quadrilateral is a parallelogram, then consecutive angles are supplementary. If both pairs of opposite sides of a quadrilateral are congruent, then the quadrilateral is a parallelogram.

Step-by-step explanation:

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Write the equation of a line in slope-intercept form that passes through the given points.
ruslelena [56]

Answer:

<h2>         y = 0.25x + 2</h2>

Step-by-step explanation:

\bold{slope\, (m)=\dfrac{change\ in\ Y}{change\ in\ X}=\dfrac{y_2-y_1}{x_2-x_1}}

(0, 2)    ⇒     x₁ = 0,  y₁ = 2

(-4, 1)     ⇒     x₂ = -4,  y₂ = 1

So the slope:

\bold{m=\dfrac{1-2}{-4-0}=\dfrac{-1}{-4}=0.25}

The point-slope form of the equation of the line passing through point (x₀,y₀) and with slope m is:  y - y₀ = m(x - x₀)

m = 0.25

(0, 2)    ⇒     x₀ = 0,  y₀ = 2

Therefore:

               y - 2 = 0.25(x - 0)

               y - 2 = 0.25x                  {add 2 to both sides}

               y = 0.5x + 2          ←  the slope-intercept form of the equation

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Which of the following is true about a parallelogram? A. Opposite angles of a parallelogram are not congruent. B. Parallelograms
mafiozo [28]

Answer: The option is D.

Step-by-step explanation:

A line that intersects another line segment and separates it into two equal parts is called a bisector.

In a quadrangle, the line connecting two opposite corners is called a diagonal. We will show that in a parallelogram, each diagonal bisects the other diagonal.

Problem

ABCD is a parallelogram, and AC and BD are its two diagonals.  Show that AO = OC and that BO = OD

Strategy

Once again, since we are trying to show line segments are equal, we will use congruent triangles. And here, the triangles practically present themselves. Let’s start with showing that AO is equal in length to OC, by using the two triangles in which AO and OC are sides: ΔAOD and  ΔCOB.

There are all sorts of equal angles here that we can use. Several pairs of (equal) vertical angles, and several pairs of alternating angles created by a transversal line intersecting two parallel lines. So finding equal angles is not a problem. But we need at least one side, in addition to the angles, to show congruency.

As we have already proven, the opposite sides of a parallelogram are equal in size, giving us our needed side.

Once we show that ΔAOD and  ΔCOB are congruent, we will have the proof needed, not just for AO=OC, but for both diagonals, since BO and OD are alsocorresponding sides of these same congruent triangles.

ABCD is a parallelogram    

Given

AD || BC                                

From the definition of a parallelogram

AD = BC                                 Opposite sides of a parallelogram are equal in size

∠OBC ≅ ∠ODA                      Alternate Interior Angles Theorem, ∠OCB ≅ ∠OAD                      Alternate Interior Angles Theorem,

ΔOBC ≅ ΔODA                     

Angle-Side-Angle

BO=OD                                Corresponding sides in congruent triangles AO=OC                             Corresponding sides in congruent triangles.

5 0
3 years ago
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