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xenn [34]
3 years ago
6

Come up with a counterexample to disprove the following

Mathematics
1 answer:
Daniel [21]3 years ago
6 0

Answer:

is there more to the question

Step-by-step explanation:

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What is the value of x in the equation<br> 0, when y = 15?<br> 4.
Tatiana [17]

Answer:

x =200

Step-by-step explanation:

\frac{1}{5}x - \frac{2}{3}(15) =30\\\\\frac{1}{5}x-10=30\\\\\frac{1}{5}x=30+10\\\\\frac{1}{5}x=40\\\\x = 40*5\\x= 200

8 0
3 years ago
Write an expression that when using th distributive property can be simplified to 12a + 18b -6c
zimovet [89]
You're looking for a common number in all the terms...6.

6(2a+3b-c)
8 0
4 years ago
What is the value of w?
DedPeter [7]
The side opposite the 30o angle is 1/2 W. That is just a property of a 30 - 60 - 90 triangle. Use that fact to set up the pythagorean relationship.

w^2 = (1/2 w)^2 + (7 * sqrt(3)) ^2
w^2 = 1/4 w^2 + 49*3
w^2 = 1/4 w^2 + 147
3/4 w^2 = 147
w^2 = 147 * 4/3
w^2 = 49 * 4 = 196
w = sqrt (196)
w = 14
4 0
4 years ago
Name one pair of parallel planes. All lines and planes that appear to be parallel are parallel.
bezimeni [28]

The parallel plane is the plane that has the same in-between distance at all points on the plane so plane ABF is parallel with plane DCG so option (C) is correct.

<h3>What is the plane?</h3>

The plane is a two dimension(2D) surface that has a surface area.

We can draw lines on a plane and two or more planes can intersect or parallel.

If two planes are parallel then the perpendicular distance between both planes must be the same.

The angle of inclination of two parallel planes with a single reference plane is also the same.

In the given cuboid the plane ABF is parallel with plane DCG.

So, ABF || DCG.

Hence "The parallel plane is the plane that has the same in-between distance at all points on the plane so plane ABF is parallel with plane DCG".

To learn more about planes,

brainly.com/question/1962726

#SPJ1

3 0
1 year ago
Triangle QRS has been translated to create triangle Q'R'S'. RS= R'S' = 10 units, angles Q and Q' are both 90 degrees. Which post
RSB [31]

The <em><u>correct answer</u></em> is:

HL

Explanation:

These will both be right triangles, as angle Q and angle Q' are both 90 degrees.

Since Q and Q' are the right angles, this means that RS and R'S' are the hypotenuses of the two right triangles.

Since Q'R'S' was created by translating QRS, a corresponding leg of both triangles will be congruent; this gives us hypotenuse-leg, or HL.

6 0
4 years ago
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