The possible rectangle's length and width are A) 1 cm and 15 cm and C) 3 cm and 5 cm
<h3>How to determine the possible rectangle's length and width?</h3>
The given parameters are
Area = 15 square cm
The area is given as
Area = 15 square cm
The formula of area is
Area = Length x Width
Using the above formula, we have:
A) 1 cm and 15 cm ⇒ 15 square cm
B) 2 cm and 7 cm ⇒ 14 square cm
C) 3 cm and 5 cm ⇒ 15 square cm
D) 4 cm and 4 cm ⇒ 16 square cm
Hence, the possible rectangle's length and width are A) 1 cm and 15 cm and C) 3 cm and 5 cm
Read more about area at:
brainly.com/question/17335144
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<u>Possible question</u>
The area of a rectangle is 15 square cm
Which of the following could be the rectangle's length and width?
(Area = length x width)
Choose all answers that apply:
A) 1 cm and 15 cm
B) 2 cm and 7 cm
C) 3 cm and 5 cm
D) 4 cm and 4 cm
You need to multiply 21 by $4.65, which gets you $97.65
Area
Answer is 2000 (after rounding to nearest thousands).
Hope this helps. - M
Answer:
<em>The</em><em> </em><em>answer is</em><em> </em><em>29</em><em> </em><em>unit</em><em>.</em>
Step-by-step explanation:
Here,
given that,
DC (l) =4z+1
CD (b)=5z+2
perimeter (p)= 132
now,
perimeter of rectangle (p) is= 2(l+b)
or, 132 = 2×{(4z+1)+(5z+2)}
or, 132= 2×(9z+3)
or, 132= 18z+6
or, 18z=132-6
or, z=126/18
or, z= 7.
therefore, 4z+1=4×7+1=29
5z+2= 5×7+2=37.
As our question is about to find AB,
DC = AB. (as opposite side of rectangle is equal).
so, the valueof AB is 29unit.
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
An equilateral polygon has congruent sides, like a rhombus.
An equiangular polygon has congruent interior angles, like a rectangle.
In other words: Equilateral doesn't necessarily have congruent INTERIOR angles while equiangular does have/need congruent interior angles.