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anzhelika [568]
3 years ago
13

Someone help I need 39-28

Mathematics
2 answers:
stiks02 [169]3 years ago
6 0

Answer:

39-28=11

Step-by-step explanation:

Mazyrski [523]3 years ago
5 0

Answer:

39- 28= 11

Step-by-step explanation:

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0.04 rounded to the nearest hundreth<br><br> and <br><br> 0.2% rounded to the nearest hundreth
ELEN [110]
To round a number, you look to the next place to the right of what you want to round to... for example, if you want to round to the nearest hundredth, you look to the thousandths place to see whether the hundredths place rounds up or down.

0.04 is already at the hundredths place so the thousandths place is zero... the answer to the nearest hundredth is 0.04.

For 0.2%, you have to convert the percentage to a decimal by dividing by 100 (move the decimal 2 places to the left).

0.2% = 0.002

So now to round to the nearest hundredth, we look to the thousandths place. The thousandths place has a 2 in it so the hundredths place rounds down. 0.2% total he nearest hundredth is 0.
7 0
3 years ago
-2(4х + 4) — 3х – 2 = 34<br> Find x
djverab [1.8K]

Answer:

x = -4

Step-by-step explanation:

Distribute the -2 into the parentheses and your equation becomes -8x - 8 - 3x - 2 = 34

Then combine the -8x and -3x as well as the -8 and -2 to have -11x - 10 = 34

Add 10 to both sides and get -11x = 44

Divide both sides by -11 for x=-4

5 0
3 years ago
Element X decays radioactively with a half-life of eight minutes. If there are 800 g of element X, how long, to the nearest 10th
Harman [31]

Answer: 41.5 min

Step-by-step explanation:

This problem can be solved with the Radioactive Half Life Formula:  

A=A_{o}.2^{\frac{-t}{h}} (1)

Where:  

A=22 g is the final amount of the radioactive element

A_{o}=800 g is the initial amount of the radioactive element  

t is the time elapsed  

h=8 min is the half life of the radioactive element  

So, we need to substitute the given values and find t from (1):  

22 g=(800 g) 2^{\frac{-t}{8 min}} (2)  

\frac{22 g}{800 g}=2^{\frac{-t}{8 min}} (3)  

\frac{11}{400}=2^{\frac{-t}{8 min}} (4)  

Applying natural logarithm in both sides:  

ln(\frac{11}{400})=ln(2^{\frac{-t}{8 min}}) (5)  

-3.593=-\frac{t}{8 min}ln(2) (6)  

Clearing t:

t=41.46 min \approx 41.5 min This is the time elapsed

7 0
3 years ago
When solving negative -1/3.(x − 15) = −4, what is the correct sequence of operations
rodikova [14]
Distribute through the parenthesis
subtract 5 from both sides
divide both sides by -1/3...or multiply both sides by -3
6 0
3 years ago
Read 2 more answers
I need mathswatch help!
11111nata11111 [884]

Answer:

6 blue flowers, there is no mode

Step-by-step explanation:

Please mark as Brainliest! :)

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7 0
3 years ago
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