All categories

3 years ago

The smallest square number which can be divisible by 11 and 5

Mathematics

1 answer:

Elena L [17]3 years ago

6 0

Answer:

3025

Step-by-step explanation:

let's look at it in this concept.

For a number to be divisible by 11 and 5. it must be a multiple of the LCM of 11 and 5.

LCM of 11 and 5=55

therefore the number is 55x, where x is a positive integer.

it is a said that the number is a perfect square

therefore the square root of 55x must be an integer.

$\sqrt{55x} = \sqrt{5 \times 11 \times x}$

the smallest value of x to make 55x a perfect square is....

$x = 11 \times 5 = 55$

Therefore the number is.... .

$55x = 55(55) = 3025$

sweet right

<h2>BRAINLIEST PLS....</h2>

You might be interested in

A 748-N man stands in the middle of a frozen pond of radius 4.0 m. He is unable to get to the other side because of a lack of fr

Ber [7]

Answer:

The man will take 64 seconds to reach to the south shore of the frozen pond.

Step-by-step explanation:

Given:

Weight of the man = 748 N Mass of the man, $(m)= \frac{W}{g}$ = $\frac{748}{9.8}$ = $76.32$ kg

Radius of the pond $(r)$ = 4 m

Mass of the textbook = 1.2 kg

Velocity at which the textbook is thrown = 4 ms^1

We have to find the velocity of the man after the throw.

Let the velocity is $V_m$ .

Now using law of conservation of momentum we can find the $V_m$ value.

$m_(_b_)V_b_(_i_) +m_(_m_)V_m_(_i_) =m_(_b_)V_b_(_f_)+m_(_m_) V_m_(_f_)$

Considering $V_m_(_f_)=V_m$

And initial velocity of both the man and book i.e $V_b_(_i_)=0,\ V_m_(i_)=0$

So,

⇒ $0 =m_(_b_)V_b_(_f_)+m_(_m_) V_m$

⇒ Plugging the values.

⇒ $V_m=-\frac{m_(_b_)V_b_(_f_)}{m_(_m_)}$

⇒ $V_m=-\frac{1.2\times 4}{76.32}$

⇒ $V_m=-0.062$ ms^-1

Here the negative velocity is meant for opposite direction of the throw.

Numerically we will write, $V_m = 0.062$

With this velocity the man will move towards south.

We have to calculate the time taken by the man to move to its south shore.

And we know $velocity(v)\times time(t) = distance(d)$

Let the time taken be $t$ and $v\times t = d$ and $d=r$ then, $V_m\times t=r$

Then

⇒ $t=\frac{radius\ (r)}{V_m}$

⇒ Plugging the values.

⇒ $t=\frac{4}{0.062}$

⇒ $t =64$ sec

The man will take 64 seconds to reach to the south shore of the frozen pond (circular).

5 0

2 years ago

Anna wants to rent movies from either Service A or Service B. Service A charges $37.92 as a subscription fee with a charge of $2

Molodets [167]

Answer:

6 is your answer :)

6 0

3 years ago

Answer my math pleaseeeeeeeee

PilotLPTM [1.2K]

Answer:

Are ni =)

Step-by-step explanation:

OK are no the picture

8 0

3 years ago

Read 2 more answers

Which matrix equation represents the system of equations? {-x+ 2y = 0 y= -2

Snowcat [4.5K]

We are given a system of equations,

$\begin{cases}-x+2y=0\\y=-2\\ \end{cases}$

This will translate into a 2x2 matrix of coefficients (because 2 equations and 2 unknowns),

$\begin{bmatrix}-1&2\\0&1\\ \end{bmatrix}$

The matrix will then be applied to the vector (lower dimensions on top),

$\begin{bmatrix}x\\y\\ \end{bmatrix}$

And the result vector will be whats on the other side of equals sign,

$\begin{bmatrix}0\\-2\\ \end{bmatrix}$

So to put everything together,

$\begin{bmatrix}-1&2\\0&1\\ \end{bmatrix}\begin{bmatrix}x\\y\\ \end{bmatrix}=\begin{bmatrix}0\\-2\\ \end{bmatrix}$

Hope this helps :)

6 0

2 years ago

I need help thank you

ycow [4]

9514 1404 393

Answer:

y = 3x +1
y = x + 3

Step-by-step explanation:

The bottom dot and the top dot are on a line with two other dots, the one at (0, 1) and the one at (1, 4). That line has a rise/run = 3/1. The point (0, 1) is its y-intercept, so its equation can be ...

y = 3x +1

The left dot and the lower right dot are on a line with three other dots. One of those (1, 4) is shared with the previous line. This line has a rise/run = 1/1. The point (0, 3) is its y-intercept, so its equation can be ...

y = x + 3

These two equations capture all of the coins.

4 0

2 years ago

The smallest square number which can be divisible by 11 and 5​

The smallest square number which can be divisible by 11 and 5