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pogonyaev
3 years ago
11

The smallest square number which can be divisible by 11 and 5​

Mathematics
1 answer:
Elena L [17]3 years ago
6 0

Answer:

3025

Step-by-step explanation:

let's look at it in this concept.

For a number to be divisible by 11 and 5. it must be a multiple of the LCM of 11 and 5.

LCM of 11 and 5=55

therefore the number is 55x, where x is a positive integer.

it is a said that the number is a perfect square

therefore the square root of 55x must be an integer.

\sqrt{55x}  =  \sqrt{5 \times 11 \times x}

the smallest value of x to make 55x a perfect square is....

x = 11 \times 5 = 55

Therefore the number is.... .

55x = 55(55) = 3025

<em>sweet</em><em> </em><em>right</em>

<h2><u>B</u><u>R</u><u>A</u><u>I</u><u>N</u><u>L</u><u>I</u><u>E</u><u>S</u><u>T</u><u> </u><u>P</u><u>L</u><u>S</u><u>.</u><u>.</u><u>.</u><u>.</u></h2>
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Answer:

<em>The slope of the line is m=6.  </em>

<em>The y-intercept is (0,−24).  </em>

<em>The equation of the line in the slope-intercept form is y=6x−24.</em>

Step-by-step explanation:

The slope of the line passing through the two points P=(x1,y1) and Q=(x2,y2) is given by m=y2−y1x2−x1.

We have that x1=2, y1=−12, x2=5, y2=6.

Plug the given values into the formula for the slope: m=(6)−(−12)(5)−(2)=183=6.

Now, the y-intercept is b=y1−m⋅x1 (or b=y2−m⋅x2, the result is the same).

b=−12−(6)⋅(2)=−24.

Finally, the equation of the line can be written in the form y=mx+b.

y=6x−24.

Answer:

The slope of the line is m=6.

The y-intercept is (0,−24).

The equation of the line in the slope-intercept form is y=6x−24.

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3 years ago
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Step-by-step explanation:

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Answer:

Where 0 < x < 3

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The location of the local maximum is at (0, 16)

Step-by-step explanation:

The given function is f(x) = (x + 2)⁴

The range of the minimum = 0 < x < 3

At a local minimum/maximum values, we have;

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f''(x) = \dfrac{ -4 \cdot (-x + 2)^3}{dx}  = -12 \cdot (-x + 2)^2

When x = 2, f''(2) = -12×(-2 + 2)² = 0 which gives a local minimum at x = 2

We have, f(2) = (-2 + 2)⁴ = 0

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Given that the minimum of the function is at x = 2, and the function is (-x + 2)⁴, the absolute local maximum will be at the maximum value of (-x + 2) for 0 < x < 3

When x = 0, -x + 2 = 0 + 2 = 2

Similarly, we have;

-x + 2 = 1, when x = 1

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Answer:

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