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pogonyaev
3 years ago
11

The smallest square number which can be divisible by 11 and 5​

Mathematics
1 answer:
Elena L [17]3 years ago
6 0

Answer:

3025

Step-by-step explanation:

let's look at it in this concept.

For a number to be divisible by 11 and 5. it must be a multiple of the LCM of 11 and 5.

LCM of 11 and 5=55

therefore the number is 55x, where x is a positive integer.

it is a said that the number is a perfect square

therefore the square root of 55x must be an integer.

\sqrt{55x}  =  \sqrt{5 \times 11 \times x}

the smallest value of x to make 55x a perfect square is....

x = 11 \times 5 = 55

Therefore the number is.... .

55x = 55(55) = 3025

<em>sweet</em><em> </em><em>right</em>

<h2><u>B</u><u>R</u><u>A</u><u>I</u><u>N</u><u>L</u><u>I</u><u>E</u><u>S</u><u>T</u><u> </u><u>P</u><u>L</u><u>S</u><u>.</u><u>.</u><u>.</u><u>.</u></h2>
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You can use the properties of logarithm to derive the simplified form of the given expression.

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