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alex41 [277]
3 years ago
7

The probability that a battery will last 10 hr or more is 0.9, and the probability that it will last 15 hr or more is 0.12. Give

n that a battery has lasted 10 hr, find the probability that it will last 15 hr or more. (Round your answer to three decimal places.)
Mathematics
1 answer:
Dahasolnce [82]3 years ago
4 0

Answer:

Answer is 13.3%

Step-by-step explanation:

  • 90 percent of the batteries will last 10 hours or exceed.
  • 12 percent  of the batteries will last 15 hours or more.

If the likelihood of these batteries is to hold for the given time period, then, out of one thousand (1000) batteries produced, nine hundred (900)  of the batteries will have long lasted 10 hours or longer and 120 of them will have lasted 15 hours or more.

The 120 which have lasted 15 hours or more must have lasted at most 10 hours or more, so they are part of the bunch that lasted 10 hours of more.

They are 12% of the total of 1000 batteries produced, but they are 15% of the 900 batteries that lasted 10 hours or more, Why? view the following:

  • 120 / 900 = 0.1333 = 13.3%

The solution which seems to be that 13.3 percent of the batteries that prolonged 10 hours or more lasted 15 hours or longer.

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A rectangular field has an area 28800 sq.meter.its length is twice as long as its width.what is the length of its sides?
AVprozaik [17]
Let 
x---------> the length side of rectangle
y---------> the width side of rectangle

we know that
x=2y-----> equation 1
area=x*y-------> 28800=x*y------> equation 2
substitute 1 in 2

28800=[2y]*y-----> 28800=2y²-------> y²=14400------> y=120 m
x=2*y----> x=2*120------> x=240 m

the answer is
the length side of rectangle is 240 m
 the width side of rectangle is 120 m


5 0
3 years ago
Find b and s. At The present time Mrs. B's age is six years more than four times her sons age. Three years ago she was seven tim
padilas [110]

Answer:

Mrs. B's age = y = 38 years

her son's age = x = 8 years

Step-by-step explanation:

To Find:

Mrs. B's age = y =?

her son's age = x = ?

Solution:

Let Mrs. B's age  be 'y' years

and her son's age be 'x' years

Three years ago Mrs B's will be (y - 3) and her son's age will be (x - 3)

According to the first given condition,

y = 6 + 4x ...............Equation ( 1 )

According to the second given condition,

(y - 3 ) = 7 (x - 3 )..........Equation ( 2 )

equating equation 1 in equation 2 we get

6 + 4x -3 = 7x - 21

7x - 4x = 21 + 3

∴ 3x=24\\\therefore x =\frac{24}{3} \\\\\therefore x =8\ years

Now substitute x in equation 1 we get

y = 6 + 4×8

y = 6 + 32

∴ y = 38 years

Mrs. B's age = y = 38 years

her son's age = x = 8 years

6 0
3 years ago
Please show work! Colton sold a total of 28 t-shirts and sweatshirts as a part of a fundrasier for his football team. If t-shirt
Dafna1 [17]
11 sweatshirts and 17 t shirts
5 0
4 years ago
Please help me i dont know how to do this
tankabanditka [31]
13x-6+95=180
Combine like terms
13x=91
Divide by 13
X=7

Two base angles are supplementary/equal 180
4 0
3 years ago
A sample was taken of the salaries of 20 employees from a large company. The following are the salaries (in thousands of dollars
seropon [69]

Answer:

21,500

Step-by-step explanation:

Given data ( in thousand ) in this year,

28 31 34 35 37 41 42 42 42 47 49 51 52 52 60 61 67 72 75 77,

If each data is increased by $ 3000 in the next year,

So, the data for the next year,

31 34 37 38 40 44 45 45 45 50 52 54 55 55 63 64 70 75 78 80,

Since, the data is already arranged in the ascending order,

The median is 51 which is between 50 and 52,

Thus, the lower half of the Data is, 31 34 37 38 40 44 45 45 45 50,

Having median Q_1=\frac{40+44}{2} = \frac{84}{2} = 42,

Upper half of the data is 52 54 55 55 63 64 70 75 78 80,

Having median Q_3=\frac{63+64}{2}=\frac{127}{2} = 63.5

Hence, the interquartile range = Q_3-Q_1

= 63.5 - 42

= 21.5

That is, the Interquartile range would be 21, 500.

7 0
4 years ago
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