I think you meant 5,244 ÷ 6 = 874.
Answer/Step-by-step explanation:
We can check if this 5,244 ÷ 6 = 874 is correct by doing it opposite.
Since it 5,244 divide 6 we can do 874 x 6.
×
======
+ 5244
=======
5244
Hence, this answer is correct.
[RevyBreeze]
Answer:
Low Q1 Median Q3 High
6 9 11 12.5 14
The interquartile range = 3.5
Step-by-step explanation:
Given that:
Consider the following ordered data. 6 9 9 10 11 11 12 13 14
From the above dataset, the highest value = 14 and the lowest value = 6
The median is the middle number = 11
For Q1, i.e the median of the lower half
we have the ordered data = 6, 9, 9, 10
here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.
i.e
median =
median =
median = 9
Q3, i.e median of the upper half
we have the ordered data = 11 12 13 14
The same use case is applicable here.
Median =
Median =
Median = 12.5
Low Q1 Median Q3 High
6 9 11 12.5 14
The interquartile range = Q3 - Q1
The interquartile range = 12.5 - 9
The interquartile range = 3.5
Answer:
The correct options are;
B) The mean and median for the security company are both lower than the mean and the median for the collections performed by other companies
B) Since the security company appear to have collected lower revenue than other companies, there is some evidence of stealing by the security company's employees
Step-by-step explanation:
We use the acronym SC for the security company and OC for the other company
SC OC
1.6 1.5
1.8 2.1
1.6 1.9
1.8 2.2
1.7 1.9
1.2 1.7
1.1 2.1
1.2 2.2
1.2 2.2
1.5 1.8
∑x 14.7 19.6
The mean is given by ∑x/n
n = 10
SC OC
∴ Mean 1.47 1.96
The median is the
Hence
SC OC
Median 1.55 2
Therefore, the mean and median for the security company are both lower than the mean and the median for the collections performed by other companies.
b) Since the security company appear to have collected lower revenue than other companies, there is some evidence of stealing by the security company's employees.