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Darya [45]
4 years ago
13

Given that g(x)=x^2-4x-5, find (g*g) (-2)

Mathematics
2 answers:
irinina [24]4 years ago
4 0

the first question...the answer is 10

see;x is our unknown number

so;27-2=25

x + 15=25

x = 25-15

x =10

10 + 15 = 25

25 + 2 = 27

Y_Kistochka [10]4 years ago
4 0
Hello :
(gog)(-2) = g(g(-2))
but g(-2) = (-2)²-4(-2)-5 =4+8-5=7
(gog)(-2) = g(g(-2)) =g(7) = 7²-4(7)-5 =49-33 =16
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9 - (-8) • 3<br> Order of Operations
andrey2020 [161]

Answer:

33

Step-by-step explanation:

Order of Operations:

1. Parenthesis

2. Exponents

3. Multiplication/Division (left to right)

4. Addition/Subtract (left to right)

Step 1: 9-(-8) • 3

Step 2: 9-(-24)

Step 3: 9 + 24

Answer: 33

7 0
3 years ago
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What is a perfect cube and how can you check if a given number is a perfect cube? Explain why.
Sholpan [36]

Answer:

Read below.

Step-by-step explanation:

A perfect cube is a number cubed (If that makes sense). Such as 3³ will equal a perfect cube because it's being multiplied by itself 3 times. 3×3×3=9. It will work for any whole number. You can check if a given number is a perfect cube by using the cube root (\sqrt[3]{x}).

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6 0
3 years ago
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A picture frame cube has a volume of 64 cubic cm. each of the six faces holds a picture of the same size as the face. what size
olganol [36]

Solving this problem is pretty straight forward. All we have to do is to find for the measure of one side since the shape is a cube so the formula for volume is:

V = s^3

where V is volume = 64 m^3, s is the measure of one side

64 m^3 = s^3

s = cuberoot (64 m^3)

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Therefore the size of the pictures are:

<span>C. 4 x 4</span>

6 0
4 years ago
Please help lol!!!!!!!
Elena L [17]

Answer:

That would be 4x - 3y + 5

Step-by-step explanation:

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8 0
3 years ago
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Given tan of theta = -2 and pi/2; find cos(2theta)
Nata [24]

Given tan of theta = -2 and pi/2; find cos(2theta)
The identity of cos (2 theta)= cos(2\theta )=\frac{1-tan^2\theta }{1+tan^2\theta }
Given tan of theta = -2 and pi/2.
So, let's plug in tan theta= -2
cos(2\theta)= \frac{1-(-2)^2}{1+(-2)^2}
=\frac{1-4}{1+4} (Squaring)
=\frac{-3}{5} (simplifying)
So, cos ( 2 theta) = -3/5.
Now we can plug in tan theta = π/2
cos(2\theta)= \frac{1-(π/2)^2}{1+(π/2)^2}
= \frac{1-pi^2/4}{1+pi^2/4} (Squaring)
=\frac{4-pi^2}{4+pi^2} Simplifying
So, cos ( 2 theta)= -3/5 and (4-pi^2)/(4+pi^2)

5 0
4 years ago
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