Ask question

Ask question

All categories

4 years ago

9

For a given recipe, 6 cups of flour are mixed with 12 cups of sugar. How many cups of sugar should be used if 16 cups of flour a

re used?

1 answer:

Sphinxa [80]4 years ago

7 0

Answer:

32 cups

Step-by-step explanation:

hope this helps plz mark brainliest

You might be interested in

What is the probability of rolling an odd or non-prime number using a 12-sided die?

andriy [413]

Answer:

D) 11/12

Step-by-step explanation:

From 1 to 12, 6 numbers are odd (1, 3, 5, 7, 9, and 11).

7 numbers are non-prime (1, 4, 6, 8, 9, 10, and 12).

2 numbers are both odd and non-prime (1 and 9).

Therefore, the probability is:

(6 + 7 − 2) / 12 = 11/12

6 0

3 years ago

Can someone please help me

mars1129 [50]

Answer:

I think the answer is b

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Please help me in this assignment.

8090 [49]

Tan(A) = opposite / adjacent
if we call opposite "a" and adjacent "b"
tan(A) = a/b
then...
tan(B) = b/a
because it's on the other angle so "b" is now opposite angle B and "a" is adjacent.

So really you just need to take the reciprocal of the given values.

6. tan(A) = 1.25
reciprocal is flipping the value and using it to divide by 1.

you can keep as decimal , 1/1.25 = 0.8
or change to fraction
1.25 = 5/4

tan(B) = 4/5 or 0.8

7. tan(B) = 0.5
1/0.5 = 2
tan(A) = 2

8. tan(B) = 1
tan(A) = 1

8 0

3 years ago

Select all the points that are on the graph of the equation 4y - 6X equals 12

liraira [26]

Answer:

4ieideerriiiriiieeoeoeoee

7 0

3 years ago

An automobile manufacturer who wishes to advertise that one of its models achieves 30 mpg (miles per gallon) decides to carry ou

Katyanochek1 [597]

Answer:

$t=\frac{29.35-30}{\frac{1.365}{\sqrt{6}}}=-1.17$

$p_v =P(t_{(5)}$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

We can say that at 5% of significance the true mean is not significantly less than 30 so then the claim that true average fuel efficiency is (at least) 30 mpg makes sense

Step-by-step explanation:

Data given and notation

The mean and sample deviation can be calculated from the following formulas:

$\bar X =\frac{\sum_{i=1}^n x_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)}{n-1}}$

$\bar X=29.35$ represent the sample mean

$s=1.365$ represent the sample standard deviation

$n=6$ sample size

$\mu_o =30$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is lower than 30 or no, the system of hypothesis are :

Null hypothesis: $\mu \geq 30$

Alternative hypothesis: $\mu < 30$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{29.35-30}{\frac{1.365}{\sqrt{6}}}=-1.17$

P-value

We need to calculate the degrees of freedom first given by:

$df=n-1=6-1=5$

Since is a one-side left tailed test the p value would given by:

$p_v =P(t_{(5)}$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

We can say that at 5% of significance the true mean is not significantly less than 30 so then the claim that true average fuel efficiency is (at least) 30 mpg makes sense

5 0

3 years ago