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3 years ago

Find the area of the rhombus.

1 answer:

5 0

To find the area of a rhombus using diagonals, you must multiple the diagonals and divide then by 2. In this case 37 * 20 is 740. 740/2 is 370. 370 is your answer

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Which statement regarding the diagram is true?

Sergeu [11.5K]

Answer

<span>m∠WXY + m∠YXZ = 180°</span>

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3 years ago

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1496 mm2 to square centimetres.

Kazeer [188]

Answer:

14.96

Step-by-step explanation:

1496mm *mm = 1496 * 1/10 cm * 1/10cm =1496/100 cm2

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3 years ago

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Which description is correct for this polynomial 4x^2+3x+5?

mash [69]

Its a quadratic trinomial

Its quadratic because the highest degree in the equation is two

Its a trinomial because there are three different terms in the equation

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2 years ago

Find the zeros of y = x2 – 6x – 4 by completing the square.

katrin [286]

Answer:

The solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

Step-by-step explanation:

Given the function

$y\:=\:x^2\:-\:6x\:-\:4$

substitute y = 0 in the equation to determine the zeros

$0\:=\:x^2\:-\:6x\:-\:4$

Switch sides

$x^2-6x-4=0$

Add 4 to both sides

$x^2-6x-4+4=0+4$

Simplify

$x^2-6x=4$

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

$x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2$

$x^2-6x+\left(-3\right)^2=13$

Apply perfect square formula: (a-b)² = a²-2ab+b²

$\left(x-3\right)^2=13$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-3=\sqrt{13}$

Add 3 to both sides

$x-3+3=\sqrt{13}+3$

Simplify

$x=\sqrt{13}+3$

now solving

$x-3=-\sqrt{13}$

Add 3 to both sides

$x-3+3=-\sqrt{13}+3$

Simplify

$x=-\sqrt{13}+3$

Thus, the solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

4 0

2 years ago

Select all the expressions that are greater than 1.

Lena [83]

Answer:

There is only 1 option!!!

6 0

2 years ago