Ask question

Ask question

All categories

3 years ago

15

The population of Algebraville is 500,000 and growing at 6.25%. How many people will live in Algebraville in 10 years? 20?

1 answer:

otez555 [7]3 years ago

8 0

This would be exponential growth
A= 500,000(1+.0625)^10
=500,000(1.0625)^10
=500,000* <span>1.83353577126
the population after 10 years= </span><span>916,767
A=500,000(1+.0625)^20
=500,000(1.0625)^20
=500,000* 3.36185342451
the population after 20 years would be= </span><span>1,680,926</span>

You might be interested in

Can someone help me ASAP please. I'll give extra points if right fr

9966 [12]

Answer:

y = -1/4x + -6

Step-by-step explanation:

6 0

2 years ago

Simplify the expression:<br> b2–3b+7+5b

MArishka [77]

The answer is :

4b+7

hope this helps!!

6 0

2 years ago

Read 2 more answers

Aaron graphed the ordered pairs generated by f(-8), f(-3), f(-2), f(1), f(2), f(5), f(6), and f(8) on a coordinate plane. He the

Amanda [17]

Answer:

f(x) is x multipled by f

Step-by-step explanation:

pls brianlist

7 0

2 years ago

Water is leaking out of an inverted conical tank at a rate of 6800 cubic centimeters per min at the same time that water is bein

Bad White [126]

Answer:

The rate at which water is being pumped into the tank is 13,913.27 cubic centimetre per minute

Step-by-step explanation:

Given that, the height of the conical tank is 13 meters and diameter is 3 meters.

Radius = $\frac32$ meters

$\therefore \frac{radius }{height}=\frac {\frac{3}{2}}{13}$

$\Rightarrow \frac{radius }{height}=\frac {3}{26}$

$\Rightarrow radius=\frac {3}{26}\times height$ ......(1)

The volume of the cone is $V=\frac13 \pi r^2 h$

Now putting $r=\frac{3}{26} h$

$V=\frac13 \pi (\frac3{26}h)^2 h$

$\Rightarrow V=\frac{3}{676} \pi h^3$

Differentiating with respect to t

$\frac{dV}{dt}=\frac{3}{676}\pi .3h^2 \frac{dh}{dt}$

$\Rightarrow \frac{dV}{dt}=\frac{9}{676}\pi h^2 \frac{dh}{dt}$

Given that, the water level is rising at a rate of 17 cm per minute when the height 1 meter= 100 cm .i.e $\frac{dh}{dt}=17$ cm/min

Putting $\frac{dh}{dt}=17$

$\frac{dV}{dt}=\frac{9}{676}\pi h^2 \times 17$

$\frac{dV}{dt}|_{h=100}=\frac{9}{676}\pi (100)^2 \times 17$

≈7,113 cubic centimetre per minute

The volume of water increases 7,113 cubic centimetre per minute while 6,800 cubic centimetre per minute is leaking out.

It means the required rate at which water is being pumped into the tank is

=(7,113+6,800)cubic centimetre per minute

=13,913 cubic centimetre per minute

4 0

3 years ago

a line that contains point (2, –2) and perpendicular to another line whose slope is –1. What is the equation of the line and gra

dolphi86 [110]

It would x - 4 = y because tge opposite reciprocal of -1 is 1 and so using point slope form y + 2 = x - 2 and when simplified youll get x - 4 = y.

5 0

3 years ago