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Mariulka [41]
4 years ago
7

Help me please! Ray BD is the angle bisector.What is the value of x?

Mathematics
1 answer:
Montano1993 [528]4 years ago
8 0

Answer:

x = 4

Step-by-step explanation:

An angle bisector divides an angle into two equal parts.  This means that you can set the two parts equal to each other and solve for x.

8x + 35 = 11x + 23

(8x + 35) - 35 = (11x + 23) - 35

8x = 11x - 12

8x - 11 x = (11x - 12) - 11x

-3x = -12

(-3x)/-3 = -12/-3

x = 4

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Find the length of each arc. Use the exact answer
xenn [34]

Answer:

D) 16π/3 ft

Step-by-step explanation:

We solve the above question using the Arc length formula when our central angle is in degrees

The formula is given as:

Arc length = 2πr × θ /360

r = 4 ft

θ = Central angle in degrees = 240°

Hence,

2 × π × 4 × 240/360

8π × 240/360

8π × 20/30

16π/3 ft

Arc length = 16π/3 ft

Option D is the correct option

7 0
3 years ago
You ran 8 miles. John ran half as far as you. Tim ran half as far as John. Chris ran half as far as Tim.
Tanya [424]
You=8
John=4
Chris=2
Tim=1
7 0
4 years ago
PLEASE ANSWER!!!!! I WILL MARK YOU AS BRAINLIEST!!!!! IT IS HIGHLY APPRECIATED!!! :)
kkurt [141]

Answer:

A number less than 4 was rolled 18 times.

The number cube was rolled 50 times. The relative frequency of rolling a number less than 4 is 36%.

3 0
4 years ago
What is the value of the expression 3y−z/y+5z when y = 6 and z = 2?
mixer [17]

\text{y}=6 \ \text{and} \ \text{z}=2\\\\\dfrac{3\text{y}-\text{z}}{\text{y}+5\text{z}}=\dfrac{3\cdot6-2}{6+5\cdot2}=\dfrac{18-2}{6+10}=\dfrac{16}{16}=\huge\boxed1

6 0
3 years ago
A statistics teacher started class one day by drawing the names of 10 students out of a hat and asked them to do as many pushups
mash [69]

Using the t-distribution, we have that the 95% confidence interval for the true mean number of pushups that can be done is (9, 21).

For this problem, we have the <u>standard deviation for the sample</u>, thus, the t-distribution is used.

  • The sample mean is of 15, thus \overline{x} = 15.
  • The sample standard deviation is of 9, thus s = 9.
  • The sample size is of 10, thus n = 10.

First, we find the number of degrees of freedom, which is the one less than the sample size, thus df = 9.

Then, looking at the t-table or using a calculator, we find the critical value for a 95% confidence interval, with 9 df, thus t = 2.2622.

The margin of error is of:

M = t\frac{s}{n}

Then:

M = 2.2622\frac{9}{\sqrt{10}} = 6

The confidence interval is:

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\overline{x} - M = 15 - 6 = 9

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The confidence interval is (9, 21).

A similar problem is given at brainly.com/question/25157574

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