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BlackZzzverrR [31]
3 years ago
12

If n is even, which represents the first consecutive even integer after n?

Mathematics
2 answers:
kow [346]3 years ago
3 0

Answer: n+2


Step-by-step explanation:

1. By definition, an even number is that number that can be divided by two.

2. Therefore, keeping this definition on mind, if you have an even number n, the next consecutive even integer after it can be obtained by adding 2.

3. Then, you can conclude the expression that represents  the first consecutive even integer after n is:

n+2



Pavel [41]3 years ago
3 0

Answer: n + 2

Step-by-step explanation: The first positive even integer on the number line is 2.

Subsequent numbers in the series are 4,6,8...

Now Even numbers are numbers that are divisible by 2 without remainders.

To find consecutive even integers, where n is even, the expression n+2 is employed.

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Use the given minimum and maximum data​ entries, and the number of​ classes, to find the class​ width, the lower class​ limits,
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Using proportions and the information given, it is found that:

  • The class width is of 14.375.
  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
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-------------------------

  • Minimum value is 19.
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  • There are 8 classes.
  • The classes are all of equal width, thus the width is of:

W = \frac{134 - 19}{8} = 14.375

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

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so the coat went down from 50 to 35, namely 15.

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3 years ago
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