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Dovator [93]
3 years ago
7

Clarence works at least 5 hours but not more than 7 hours. he earns $11.60 per hour. the function f(t)=11.6t represents the amou

nt of money he earns for working t hours. choose the practical domain and the practical range for this situation. there are exactly 2 correct answers. options: the practical domain is all real numbers. the practical domain is all real numbers from 5 to 7, inclusive. the practical range is all real numbers from 58 to 81.2, inclusive the practical range is all real numbers from 5 to 7, inclusive.
Mathematics
2 answers:
Strike441 [17]3 years ago
6 0
What was the answer? i'm on the same quiz and can't seem to figure it out.

Pavel [41]3 years ago
4 0
Function: f(t) = 11.6 t

Restrictions: 5 ≤ t ≤ 7

Domain: possible values of t: all real values between 5 and 7 inclusive

Range: possible values of f(t): from 11.6 * 5 to 11.6 *7 = from 58 to 81.2, inclusive.

Answer:

the practical domain is all real numbers from 5 to 7, inclusive. and the practical range is all real numbers from 58 to 81.2

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Which expressions can be used to find m∠ABC? Check all that apply.
valina [46]

Answer:

\cos^{-1}(\frac{6.3}{9.8})

\sin^{-1}(\frac{7.5}{9.8})

Step-by-step explanation:

Recall the mnemonics SOH-CAH-TOA

The sine ratio is the length of the opposite side expressed over the hypotenuse.

\sin m\angle ABC=\frac{7.5}{9.8}

Take the sine inverse of both sides to get;

m\angle ABC=\sin^{-1}(\frac{7.5}{9.8})

The cosine ratio is the length of the adjacent side expressed over the hypotenuse.

\cos m\angle ABC=\frac{6.3}{9.8}

Take the cosine inverse of both sides to get;

m\angle ABC=\cos^{-1}(\frac{6.3}{9.8})

4 0
4 years ago
Brainliest for correct answer
Tcecarenko [31]
1.not a function 2. Not a function 3.function
3 0
3 years ago
A data set with a mean of 34 and a standard deviation of 2.5 is normally distributed
tresset_1 [31]

Answer:

a) z= \frac{34-34}{2.5}= 0

z= \frac{39-34}{2.5}= 2

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

b) P(X

z= \frac{31.5-34}{2.5}= -1

So one deviation below the mean we have: (100-68)/2 = 16%

c) z= \frac{29-34}{2.5}= -2

z= \frac{36.5-34}{2.5}= 1

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%

Step-by-step explanation:

For this case we have a random variable with the following parameters:

X \sim N(\mu = 34, \sigma=2.5)

From the empirical rule we know that within one deviation from the mean we have 68% of the values, within two deviations we have 95% and within 3 deviations we have 99.7% of the data.

We want to find the following probability:

P(34 < X

We can find the number of deviation from the mean with the z score formula:

z= \frac{X -\mu}{\sigma}

And replacing we got

z= \frac{34-34}{2.5}= 0

z= \frac{39-34}{2.5}= 2

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

For the second case:

P(X

z= \frac{31.5-34}{2.5}= -1

So one deviation below the mean we have: (100-68)/2 = 16%

For the third case:

P(29 < X

And replacing we got:

z= \frac{29-34}{2.5}= -2

z= \frac{36.5-34}{2.5}= 1

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%

7 0
3 years ago
What is the value of n? 9×27+2×31-28=n
Vladimir [108]
So,

9*27 + 2*31 - 28 = n

We use PEMDAS.

Multiply from left to right.
243 + 2*31 - 28 = n
243 + 62 - 28 = n

Add or subtract from left to right.
305 - 28 = n
277 = n
4 0
4 years ago
Points RR, LL, and SS are:
vovikov84 [41]

Answer: C

Step-by-step explanation:

8 0
4 years ago
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