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Dovator [93]
3 years ago
7

Clarence works at least 5 hours but not more than 7 hours. he earns $11.60 per hour. the function f(t)=11.6t represents the amou

nt of money he earns for working t hours. choose the practical domain and the practical range for this situation. there are exactly 2 correct answers. options: the practical domain is all real numbers. the practical domain is all real numbers from 5 to 7, inclusive. the practical range is all real numbers from 58 to 81.2, inclusive the practical range is all real numbers from 5 to 7, inclusive.
Mathematics
2 answers:
Strike441 [17]3 years ago
6 0
What was the answer? i'm on the same quiz and can't seem to figure it out.

Pavel [41]3 years ago
4 0
Function: f(t) = 11.6 t

Restrictions: 5 ≤ t ≤ 7

Domain: possible values of t: all real values between 5 and 7 inclusive

Range: possible values of f(t): from 11.6 * 5 to 11.6 *7 = from 58 to 81.2, inclusive.

Answer:

the practical domain is all real numbers from 5 to 7, inclusive. and the practical range is all real numbers from 58 to 81.2

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Read 2 more answers
The ratio of the number of men to the number of women in a sports club is 5:2.
user100 [1]

Let the number of men and the number of women in the beginning be x and y

Now,\sf  \frac{x} {y} =\frac{5}{2} \\\\\sf=2x=5y \\\\\sf=x=\frac{5y}{2}

Now, In 2nd case,

No. Of men=x-63 and no. Of women =y-12

Now,the ratio becomes\frac{x-63}{y-12}=\frac{7}{4} \\\\\sf=4(x-63)=7(y-12) \\\\\sf=4x-252=7y-84 \\\\\sfPutting,\:x=\frac{5y}{2}\:in\: 4x-252=7y-84\:we\: get, \\\\\sf10y-252=7y-84 \\\\\sf=10y-7y=252-84 \\\\\sf=3y=168 \\\\\sf=y=56 \\\\\sf=\boxed{Y=56}

Now,we have, 2x=5y

Putting the value of Y=56 in 2x=5y,we get,

\sf 2x=5\:x\:56 \\\\\sfx=\frac{5\:x\:56}{2} \\\\\sfx=\frac{5\:x\: \cancel{56}\:\:28}{ \cancel{2}} \\\\\sf=x=5\: x\: 28 \\\\\sfx=140 \\\\\sf\boxed{x=140}

Hence, the number of men was 140 and the no. of women was 56

Hi...I am from India.. Where are you from?

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