(a+3)(a-2)
(a² -2a +3a - 6) =0
(a² + a - 6 ) = 0
Use splitting the middle term
a² + 3a - 2a - 6 = 0
a(a+3) - 2(a+3) = 0
(a-2)(a+3) = 0
Values of a are
a - 2 = 0
a = 2 .....(i)
a+3 = 0
a = -3 .....(ii)
Answer:
second one I believe
Step-by-step explanation:
Answer:
<em>x
</em> = 6
Step-by-step explanation:
<u>Create equivalent expressions in the equation that all have equal bases, then solve for</u> <em>x</em>
.
<em>x</em> = 6
<em>brainliest pls</em>
Answer:
y = - 4x + 16
Step-by-step explanation:
Assuming you require the equation of the line passing through the points.
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (3, 4) and (x₂, y₂ ) = (5, - 4)
m =
=
= - 4, thus
y = - 4x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (3, 4), then
4 = - 12 + c ⇒ c = 4 + 12 = 16
y = - 4x + 16 ← equation of line