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Lostsunrise [7]
3 years ago
12

A rectangular field is 450 meters long and 300 meters wide. What is the area of the field in square kilometers?

Mathematics
1 answer:
sp2606 [1]3 years ago
7 0
135000 meters and 135 kilometers
450 * 300 
135000 then you convert -> 135
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3 years ago
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What is 2/5-3/10 equal to
Ilia_Sergeevich [38]

Answer:

1/10

Step-by-step explanation:

2/5=4/10

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7 0
3 years ago
a rectangle has a length of 14 meters and a width of 200 centimeters. What is the area of the rectangle in meters?
Alborosie

Answer:

a=28m^2

Step-by-step explanation:

Given:

l=14m

w=200cm

Required

a=?

w in meters

Formula:

1m=100cm

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4 0
3 years ago
the perimeter of a semicircle is 108 cm what is the perimeter of the square drawn on the diameter of the semicircle ​
Andreas93 [3]

Answer:

Step-by-step explanation:

the perimeter of the semi-circle would be the diameter plus the circumference of half of the circle.  

They want to know the perimeter of a square using the diameter of the sem-circle as ONE side, so the perimeter of the square would be 4 times the ONE side.

We should recall:

diameter = 2 times the radius     circumference of a cirlce = 2π r

How do we find the diameter of the of the semi circle?

The perimeter of the semi circle is given as 108 cm

Perimeter of the semicirle =    2r + π r         diameter plus semi circumference

                                  108   =   r ( 2 + π)           factor out the r and solve for r

                     108 / (2 + π)   =   r                       divide both sides by ( 2 + r)

Now we know r, the perimeter of the squqre is 4 times 2r  or  8r

           perimeter of square = 8  [ 108 / (2 + π) ]               π  I used 3.14

                                             =  864 / 5.14

                                             =   168.1 cm       I got rounded to nearest tenth    

<em>When I re-checked by work I found a few math,  logic and calculation errors.  Please re-check my answer for any more mistakes.</em>

       

4 0
3 years ago
Which equations represent the asymptotes of the hyperbola?
makvit [3.9K]

Answer:

  see below

Step-by-step explanation:

The equation of the hyperbola can be written as ...

  ((x -h)/a)² -((y -k)/b)² = 1

This has asymptotes ...

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Solving for y, we have ...

  y = ±(b/a)(x -h) +k

Filling in the given values a=6, b=8, h=1, k=2, we have ...

  y = ±8/6(x -1) +2

  y=\dfrac{\pm4x\mp4+6}{3}\\\\\boxed{y=\dfrac{4x+2}{3}\ \text{and }y=\dfrac{10-4x}{3}}

4 0
3 years ago
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