Answer:
![P(x)=(x+9)(x^2-7x+52)+3](https://tex.z-dn.net/?f=P%28x%29%3D%28x%2B9%29%28x%5E2-7x%2B52%29%2B3)
Step-by-step explanation:
We are given that
![P(x)=x^3+2x^2-11x+471](https://tex.z-dn.net/?f=P%28x%29%3Dx%5E3%2B2x%5E2-11x%2B471)
![d(x)=x+9](https://tex.z-dn.net/?f=d%28x%29%3Dx%2B9)
We have to find the value of Q(x) and Remainder R(x).
Quotient, ![Q(x)=x^2-7x+52](https://tex.z-dn.net/?f=Q%28x%29%3Dx%5E2-7x%2B52)
Remainder,![R(x)=3](https://tex.z-dn.net/?f=R%28x%29%3D3)
We know that
![Dividend=Divisor\times Quotient+Remainder](https://tex.z-dn.net/?f=Dividend%3DDivisor%5Ctimes%20Quotient%2BRemainder)
![P(x)=(x+9)(x^2-7x+52)+3](https://tex.z-dn.net/?f=P%28x%29%3D%28x%2B9%29%28x%5E2-7x%2B52%29%2B3)
More than 2 ... there is a right and a obtuse i think
81 more than x
more than means add
81 more than x
x+81 or 81+x
Answer:
-6<x<-9
Step-by-step explanation:
if x+9<0 and 2x>-12
x<-9
x>-6
X is smaller than -9 but greater than -6.
The solution is -6<x<-9
Answer:
(600 mi) × (5280 ft/mi) × (12 in/ft)
Step-by-step explanation:
A "unit multiplier" is a multiplier that has a value of 1. That is, the numerator and denominator have the same value. For units conversion problems, the numerator quantity has the units you want, and the denominator quantity has the units you're trying to cancel.
You have units of miles. You know that ...
1 mile = 5280 feet
1 foot = 12 inches
You want to get to units of inches. With these conversion factors, you can do it in two steps (as the problem requests). The first conversion is from miles to feet using the unit multiplier (5280 feet)/(1 mile). This gives you a number of feet.
Then the second conversion is from feet to inches, so you use the one that lets you put inches in the numerator and feet in the denominator:
(12 inches)/(1 foot)
When you multiplie these all out, units of miles and feet cancel, and you're left with inches.
_____
With the above conversion factors, you can write unit mulipliers of either ...
(5280 ft)/(1 mi) . . . to convert to feet
or
(1 mi)/(5280 ft) . . . to convert to miles.