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Elan Coil [88]
3 years ago
8

There are 30 students in Mrs. Woodward’s class, and 1/5 of the class has their own cell phone. Of this group of students, 1/2 of

them are allowed to use social media. How many of the students have a cell phone and can use social media?
Mathematics
1 answer:
olga_2 [115]3 years ago
3 0

Answer:

3 students

Step-by-step explanation:

There are 30 students in Mrs. Woodward’s class.

\dfrac{1}{5} of the class has their own cell phone, so

\dfrac{1}{5}\cdot 30=\dfrac{1}{5}\cdot \dfrac{30}{1}=6

students have their own cell phones.

\dfrac{1}{2} of those 6 students are allowed to use social media. So,

\dfrac{1}{2}\cdot 6=\dfrac{1}{2}\cdot \dfrac{6}{1}=3

students are allowed to use social media.

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Answer:

This is a personal reflection of your own thoughts and feelings

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example its not accurate because there are circumstances that may get in the way or bring you down too often. But to compensate that you can try to listen more.

Another example

example it is accurate because i have thought of 4 major things about why health is this level and have accounted for the mind and body elements as well as my own awareness to comparison and reflection in what i strive or to what is should strive to be.

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Solve for m 1/C+1/m=1/z
9966 [12]
Answer:  " m = zC / (C − z) " .
___________________________________
Explanation:
_________________________
Given:  1/C + 1/m = 1/z ;  Solve for "m".

Subtract  "1/C" from each side of the equation:
____________________________________
1/C + 1/m − 1/C = 1/z − 1/C  ;

to get:  1/m = 1/z − 1/C ;
____________________________________
Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
_________________

mzC {1/m = 1/z − 1/C} ;

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Factor out an "m" on the "right-hand side" of the equation:

zC = m(C − z) ;  Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;

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zC/ (C − z) = m ;   ↔   m = zC/ (C − z) .
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