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Trava [24]
3 years ago
12

Simplify. 15 X plus 2Y plus X plus 7X plus 8Y

Mathematics
1 answer:
disa [49]3 years ago
8 0

Answer:

23x+10y

Step-by-step explanation:

add all x variables and all y variables together

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Hey everyone can someone please help me with 5c :)
Lostsunrise [7]

Answer:

A=23512.32

Step-by-step explanation:

The equation for the area of a cylinder is A=2πrh+2πr^2

If we substitute the radius and height, the equation would be A=2π(60)(2.4)+2π(60)^2

π can be shortened to 3.14 so it's A=2(3.14)(60)(2.4)+2(3.14)(60)^2

We're left with 904.32+22608

So the answer is 23512.32

5 0
3 years ago
Helpppp<br> Solve for x.
SVEN [57.7K]

Answer:

x = 28.744

Step-by-step explanation:

Seeing as this is a right triangle, and you're given an angle, an unknown measurement to the opposite side, and the measure of the adjacent side. You can use trig functions. In this case, tangent, because you are given the opposite and adjacent, and tangent covers opposite/adjacent.

Tan(32)=x/46

Tan(32)46=x

28.744=x

5 0
2 years ago
The radius of a sphere is 11 cm.what is the surface area of the sphere? Round to the nearest tenth.
Vanyuwa [196]

Answer:

The answer is

<h2>1520.5 cm²</h2>

Step-by-step explanation:

Surface area of a sphere is given by

S = 4πr²

where r is the radius

From the question r = 11cm

So the surface area of the sphere is

4π(11)²

= 4(121)π

= 484π

= 1520.5308

Which is

1520.5 cm² to the nearest tenth

Hope this helps you

8 0
3 years ago
Where is the blue dot on the number line?
earnstyle [38]

<em>Answer:</em>

–6.8

<em>Method:</em>

Counting backwards from –7 to –6.5

5 0
2 years ago
Read 2 more answers
Pls answer the question attached
barxatty [35]

\huge\mathfrak{\underline{answer:}}

\large\bf{\angle ACD = 105°}

__________________________________________

\large\bf{\underline{Here:}}

  • BCD is an isosceles right triangle , right angled at D
  • ABC is an equilateral triangle

\large\bf{\underline{To\:find:}}

  • ∠ ACD

\large\bf{In\: triangle\:ABC:}

❒ Sum of all angles is 180° , since it is an equilateral triangle all the three angles would be same

\large\bf{\underline{So}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{⟼\angle ACB = \frac{180}{3}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{⟼\angle ACB = 60°}

\large\bf{In\: triangle\:BDC}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{⟼\angle D = 90°}

\bf{⟼\angle DBC =\angle DCB }(Isosceles triangle)

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{⟼\angle DBC + \angle BDC + \angle DCB = 180° }

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{⟼2\angle DCB + 90° = 180°}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{⟼2\angle DCB = 180 -90}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{⟼\angle DCB = \frac{90}{2}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{⟼\angle DCB = 45°}

\large\bf{\underline{Therefore,}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{⟹\angle ACD = \angle ACB + \angle DCB}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{⟹\angle ACD = 60+45}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{⟹\angle ACD = 105°}

6 0
3 years ago
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