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2 years ago

12

Simplify. 15 X plus 2Y plus X plus 7X plus 8Y

1 answer:

disa [49]2 years ago

8 0

Answer:

23x+10y

Step-by-step explanation:

add all x variables and all y variables together

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mina [271]

Follow the link above.

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3 years ago

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A young lady started working at In N Out Burger:

kogti [31]

Answer:

Step-by-step explanation:

6. 13/hour

7. R=income/hours worked so 221/17=13. Not sure if that is what they are asking for.

8. Not sure. Is it $13/hour?

9. still guessing but the constant is $13/hour so to determine how many hours need to be worked to reach $1000, you divide. $1000/13=Approximately 77 hours.

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3 years ago

What sets does radical 12 belong to

adoni [48]

Step-by-step explanation: The square root of 12 is represented in the radical form as √12 which is equal to 2√3. Since, 2√3 cannot be further simplified, hence such roots are called surds.

3 0

2 years ago

Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o

Brrunno [24]

Answer:

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

$Sin\ C = \frac{h}{a}$

Make h the subject:

$h = aSin\ C$

Also, in BOC (Using Pythagoras)

$a^2 = h^2 + x^2$

Make $x^2$ the subject

$x^2 = a^2 - h^2$

Substitute $aSin\ C$ for h

$x^2 = a^2 - h^2$ becomes

$x^2 = a^2 - (aSin\ C)^2$

$x^2 = a^2 - a^2Sin^2\ C$

Factorize

$x^2 = a^2 (1 - Sin^2\ C)$

In trigonometry:

$Cos^2C = 1-Sin^2C$

So, we have that:

$x^2 = a^2 Cos^2\ C$

Take square roots of both sides

$x= aCos\ C$

In triangle BOA, applying Pythagoras theorem, we have that:

$AB^2 = h^2 + (b-x)^2$

Open bracket

$AB^2 = h^2 + b^2-2bx+x^2$

Substitute $x= aCos\ C$ and $h = aSin\ C$ in $AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2$

Open Bracket

$AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C$

Reorder

$AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C$

Factorize:

$AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C$

In trigonometry:

$Sin^2C + Cos^2 = 1$

So, we have that:

$AB^2 = a^2 * 1 + b^2-2abCos\ C$

$AB^2 = a^2 + b^2-2abCos\ C$

Take square roots of both sides

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

6 0

3 years ago

Pls need help!!!! Giving brainliest to the person that gives me the right awnser

jeka57 [31]

Answer:

you only have the answer choices not the question itself

could you please attach the question so i can help?

6 0

2 years ago