Let the two numbers be x and y.
According to your question;
x + y = 7
10y + x = 10x + y + 9
By equation 1 ; x = 7-y
Substituting the value of x ;
10y + ( 7 -y) = 10(7-y) + y + 9
9y + 7 = 70 -10y + y + 9
9y + 7 = 70 - 9y + 9
=> 18y = 70 -7 + 9
=> 18y = 72
=> y = 4
Substituting for x ;
x = 7 - y
=> x = 7 -4
=> x = 3
Thus, x = 3 and y = 4;
=> The number is 34.
X2 + y2 = 29
Center of the circle
x=0 and y=0
Therefore the slope of the line perpendicular to the tangent line
(y2-y1) / (x2-x1)
(5-0) / (2-0)
5/2
so the slope of the tangent
-2/5
General equation for the line
y = mx + c
if the line satisfies with the point (2,5)
5 = 2m + c
m = -2/5
5 = 2 * (-2/5) + c
c = 5 + (4/5)
c = 29/5
Therefore the equation of the line
y = mx + c
y = (-2/5) m + 29/5
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