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alekssr [168]
4 years ago
14

Is ∆JKL ≅ ∆KJM ? Justify your answer below.

Mathematics
2 answers:
poizon [28]4 years ago
8 0

Answer:

Yes.

Step-by-step explanation:

__                               __

KL is congruent to JM

<K is congruent to <J

<M is congruent to <L

KatRina [158]4 years ago
4 0

Answer : Yes, ΔJKL ≅ ΔKJM

Step-by-step explanation :

The following combinations of the congruent triangle facts  will be sufficient to prove triangles congruent.

The combinations are:

(1) SSS (side-side-side) : If three sides of a triangle are congruent to three sides of another triangle then the triangles are congruent.

(2) SAS (side-angle-side) : If two sides and included angle of a triangle are congruent to another triangle then the triangles are congruent.

(3) ASA (angle-side-angle) : If two angles and included side of a triangle are congruent to another triangle then the triangles are congruent.

(4) RHS (right angle-hypotenuse-side) : If the hypotenuse and leg of one right triangle are congruent to the corresponding parts of another right triangle, the right triangles are congruent.

As we are given two triangles.

Prove : ΔJKL ≅ ΔKJM

As,

Side LK = Side MJ    (side)

Side KJ = Side JK     (common side)

∠K = ∠J                     (angle)

That means, in this two sides and an angle of a triangle are equal to another triangle then the triangles are congruent.

So, ΔJKL ≅ ΔKJM  (By SAS congruency)

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a right Triangle has one angle Measuring 90 degrees and another angle Measuring 30 degrees what is The Measure of The 3rd angle
In-s [12.5K]
60 degrees cause triangles equal 180° and 90+30=120 and 180-120=60°
4 0
3 years ago
(f- g)(x) =<br> A. x2 + x-4<br> B. x2 + x + 4<br> C. 12- X+6<br> D. x2+x+6
kirill [66]

Step-by-step explanation:

I rlly think it is c.12-×+4

5 0
3 years ago
Mrs. Yang bought 5 chickens and 3 ducks for $81. A chicken cost $5 more than a duck.
anygoal [31]

The cost of each duck is $ 7 and cost of each chicken is $ 12.

Step-by-step explanation:

Given,

5 chickens and 3 ducks are bought by $ 81

A chicken costs $ 5 more than a duck.

To find the cost of each duck and cost of each chicken.

Let,

The cost of each duck = x

The cost of each chicken = x+5

According to the problem,

5(x+5)+3x = 81

or, 5x+25+3x = 81

or, 8x = 81-25

or, 8x = 56

or, x = 7

Hence,

The cost of each duck = $ 7

The cost of each chicken = $ 7+5 = $ 12

8 0
4 years ago
Whiskers the cat weighs 2 2/3 kg. Piglo weighs 4kg. For each question , write a myipulcation and a division equation, decide whe
Liula [17]

Answer:

1) x= 3/2=  1 1/2

2) x=  2/3

Step-by-step explanation:

1)How many times as heavy as  Whiskers is  Piglio?

a) Write a multiplication equation for the question.

2 2/3 kg  * [x]= 4kg

b) Write a division equation for the question.

4/ 2 (2/3) = x

c) Is the answer greater than 1 or less than 1?

Ans) Greater than 1                      

d) Find the answer

4/ 8/3= x

x= 3/2= 1 1/2

Pigilo is 1 1/2 times as heavy as whiskers

2)How many times as heavy as Piglio is Whiskers?

a) Write a multiplication equation for the question.

4 kg  * [x]=  2 2/3 kg

b) Write a division equation for the question.

2 (2/3)/4  = x

c) Is the answer greater than 1 or less than 1?

Ans) Less than 1                      

d) Find the answer

 8/3/4= x

  8/3 * 1/4= x

   2/3= x

Whiskers is 2/3 times as heavy as Pigilo.

5 0
3 years ago
Let u=(-1,3), v=( 2,4) , and w= (2,-5) . Find the component forms of the following vectors. -4 \mathrm{w}
zvonat [6]

Applying the rules of addition and scalar multiplication of vectors, –4w = (–8, 20) and –4u + w = (6, –7)

In the 2D coordinate system, vectors can be split into x-component and y-component.

we can write, for example, a vector r = (2,–6), which means:

x-component = 2

y-component = –6

  • Addition / subtraction of vectors: Just add or subtract the corresponding components.
    For example: r = (2,–6) and s = (-2,3)
    Then,
    r + s = (2,–6) +  (-2,3) = (2–2, –6+3) = (0,–3)
  • Scalar multiplication: Multiply each component by the given scalar.
    For example: r = (2,–6)
    Then,
    6r = 6.(2,–6) = (6 . 2, 6 . (–6)) = (12,–36)

In the given problem:

u = (-1,3), v = ( 2,4) , and w = (2,-5)

Then,

–4w =  –4(2, –5)

       = (–4 . 2, –4. (–5)) = (–8, 20)

–4u + w =  –4(-1,3) + (2, –5)

             = (–4.(–1), –4 . 3) +(2, –5)

             =(4, –12) + (2, –5)

             = (4+2, –12–(–5)) = (6, –7)

Learn more about vector addition and scalar multiplication here:

brainly.com/question/13592198

#SPJ4

5 0
1 year ago
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