$\begin{array}{l}\text{We\ have\ } \alpha +\beta =90\ \text{and} \ \beta =\alpha +32\text{\ then}\\\\\alpha +\alpha +32=90\\\\\Longrightarrow 2\alpha =90-32\\\\\Longrightarrow \alpha =\frac{58}{2} =29\\\\\therefore \beta =29+32=61\\\\\therefore \boxed{\text{The\ larger\ angle\ is\ 61\ degrees}}\end{array}$

5 0

3 years ago

What is the value of y if x = 4

Zina [86]

Answer:

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4 0

3 years ago

NEED DESPERATE ANSWER

stepan [7]

The answer to this question is A.–2 < x ≤ 4. Hope this helps

7 0

4 years ago

The hypergeometric distribution can be approximated by either the binomial or the poisson distribution. let x have the hypergeom

sasho [114]

I have this problem on a textbook that doesn't have a solution. It is:

Let

f(x)=(rx)(N−rn−x)(Nn),f(x)=(rx)(N−rn−x)(Nn),and keep p=rNp=rN fixed. Prove thatlimN→∞f(x)=(nx)px(1−p)n−x.limN→∞f(x)=(nx)px(1−p)n−x.

Although I can find lots of examples using the binomial to approximate the hypergeometric for very large values of NN, I couldn't find a full proof of this online.

Anyway... I hoped this helped!

6 0

3 years ago