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Artyom0805 [142]

3 years ago

14

Compute the perimeter of the rectangle using the distance formula. (round to the nearest integer)

1 answer:

Tems11 [23]3 years ago

7 0

do you have a picture

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Find the center and radius of the circle with equation (x + 7) + (y + 5)2 = 81.

vesna_86 [32]

Answer:

rtjgdesss eeevywxx13 46

7 0

4 years ago

Estimate -9 1/6 + 2 1/3 + (-1 7/8) I have more questions so if you want more just simply ask.

BigorU [14]

-8.70833333333 about but you can round to the nearest tenth (-8.7) or nearest whole number (-9)

4 0

4 years ago

According to the Distributive Property, a(b + c) = ab + ac for all real

solong [7]

ab + ac + ad is the same as a(b + c + d) according to the distributive property

5 0

3 years ago

There were 567 people at a concert when a band started playing. After each song, only one-third of the people stayed to hear the

emmasim [6.3K]

To write the function correctly, it is important to assign variables correctly and understand the situation of the problem clearly. For this, we let y the number of people and x as the number of songs played.

At x = 0 y = 567
at x = 1 y = 567 - 567(1/3)
at x = 2 y = 567 - 567(1/3)(1/3)
at x = 3 y = 567 - 567(1/3)(1/3)(1/3)

Therefore, the number of people left after x songs would be represented by the equation:

y = 567 - 567(1/3)x
y = 567 ( 1- x/3 )

8 0

3 years ago

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Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

Viktor [21]

Answer:

Therefore $k= \frac{ln2 }{18}$ , A=184

Step-by-step explanation:

Given function is

$T(t)=230 -e^{-kt}$

where T(t) is the temperature in °C and t is time in minute and A and k are constants.

She noticed that after 18 minutes the temperature of the pie is 138°C

Putting T(t) =138°C and t= 18 minutes

$138=230 -Ae^{-k\times 18}$

$\Rightarrow -Ae^{-18k}=138-230$

$\Rightarrow Ae^{-18k}=92$ .....(1)

Again after 36 minutes it is 184°C

Putting T(t) =184°C and t= 36 minutes

$184=230-Ae^{-k\times 36}$

$\Rightarrow Ae^{-36k}=230-184$

$\Rightarrow Ae^{-36k}=46$ .......(2)

Dividing (2) by (1)

$\frac{Ae^{-36k}}{Ae^{-18k}}=\frac{46}{92}$

$\Rightarrow e^{-18k}=\frac{46}{92}$

Taking ln both sides

$ln e^{-18k}=ln\frac{46}{92}$

$\Rightarrow -18k =ln (\frac12)$

$\Rightarrow -18k= ln1-ln2$

$\Rightarrow k= \frac{ln2 }{18}$

Putting the value k in equation (1)

$Ae^{-18\frac{ln2}{18}}=92$

$\Rightarrow A e^{ln2^{-1}}=92$

$\Rightarrow A.2^{-1}=92$

$\Rightarrow \frac{A}{2}=92$

$\Rightarrow A= 92 \times 2$

⇒A= 184.

Therefore $k= \frac{ln2 }{18}$ , A=184

7 0

3 years ago