Sub x = 2-y^2 to Q, we get:
Q = 3(2-y^2)*y^2
let y^2 = k
Q = 3(2-k)k = 3(2k-k^2)
2k-k^2 has a max when k = 1
Then y^2 = 1 -> y = 1 or -1
Answer: correct answer is B
Step-by-step explanation: I know this because for example if you run one mile it will take you less time than it would if you walked 1 mile
Answer:
Por el teorema de 30 grados en un triangulo rectangulo la linea roja es 
veces la longitud del cateto opuesto al angulo de de 30. Por tanto la linea roja será:
Luego
Answer:
23.27 - 5. 3 = 17.97
Step-by-step explanation:
If your answer was d) 3.6 , then you are correct!
