From the definition of the secant line we get that the average rate of change of $P(x) = -0.015\cdot x^{2}+1.2\cdot x -11.5$ , where $x$ is the selling price of the product, measured in dollars per unit, is:

$r = \frac{P(55)-P(50)}{55-50}$ (1)

Now we evaluate the function at each bound:

x = 50

$P(50) = -0.015\cdot (50)^{2}+1.2\cdot (50)-11.5$

$P(50) = 11$

x = 55

$P(55) = -0.015\cdot (55)^{2}+1.2\cdot (55)-11.5$

$P(55) = 9.125$

Then, the average rate of change is:

$r = \frac{9.125-11}{55-50}$

$r = -0.375$

Hence, the profit decreases by $ 375 for every $ 1 increase in the selling price.

8 0

3 years ago

Find the solution of the differential equation that satisfies the given initial condition.

Ann [662]

Answer:

I don’t know

Step-by-step explanation:

5 0

3 years ago

What is the slope of the line passing through the points -2,6 and 0,4

tensa zangetsu [6.8K]

x : -2 , 0

y: 6, 4

×: -2

y: 2

2/-2

8 0

3 years ago