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Sloan [31]
3 years ago
12

On Rocko's 6th birthday, he was 3 feet, 10 inches. On Rocko's 11th birthday, he was 4 feet, 8 inches, How many inches per year w

as Rocko growning?
Mathematics
1 answer:
enyata [817]3 years ago
5 0
2 inches per year bc it’s over 5 years and he grew 10 inches and 10/5 is 2
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I need help right away with the next problem.
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  see below

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To convert the numbers to percentages, divide each number by the table total (80) and multiply by 100%. That is equivalent to multiplying each number by 1.25%. For example, 18·1.25% = 22.5% (middle table number).

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How much money, in dollars, is available on his card after he takes 0<br> rides?
snow_tiger [21]

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However much he had on his card in the first place.

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2 years ago
An octagonal swimming pool has a base area of 22 square feet The pool is 3 feet deep How many cubic feet of water can the pool h
LenKa [72]

The pool can hold 65.84 ft³ of water

<u>Explanation:</u>

Given:

Shape of pool = octagonal

Base area of the pool = 22 ft²

Depth of the pool = 3 feet

Volume, V = ?

We know:

Area of octagon = 2 ( 1 + √2) a²

22 ft² = 2 ( 1 + √2 ) a²

\frac{11}{1+\sqrt{2} } = a^2

a² = \frac{11}{2.42}

a² = 4.55

a = 2.132 ft

Side length of the octagon is 2.132 ft

We know:

Volume of octagon = 2(1+\sqrt{2} ) X (a)^2 X h

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8 0
3 years ago
Help meeeeedkxkdjsjs
Alex
18 - (8 - 3 • (2t + 5)) = 0



6t + 25 = 0



3.1 Solve : 6t+25 = 0

Subtract 25 from both sides of the equation :
6t = -25
Divide both sides of the equation by 6:
t = -25/6 = -4.167

Final answer is

t = -25/6 = -4.167
5 0
3 years ago
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