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4 years ago

Solve for x. 2x2 – 40x + 200 = 0

Mathematics

2 answers:

Marina CMI [18]4 years ago

7 0

Answer:

x = 5.1

Step-by-step explanation:

You would start by using PEMDAS to multiply 2 by 2 and to simplify the left side of the equation.

4 - 40x + 200 = 0

Then because you can't subtract 40x from 4 or add 40x with 200, you would add 40x onto both sides to get rid of the -40x on the left side.

4 + 200 = 40x

Adding on, you would simplify the left side again to get...

204 = 40x

Then by dividing both sides by 40 to get only x on one side...

204/40 = 40x/40

And simplifying it further you get your answer.

x = 5.1

Eduardwww [97]4 years ago

5 0

Answer:

5.1

Step-by-step explanation:

you subtract 200 from 0 which =-200 then you can multiply 2 and 2 which =4 so then it's 4 -40x=-200 then u add -4 and -204 which is -204 so then the equation is -40x=-204 then u divide -204 by -40 to get 5.1 so x = 5.1. not sure if I did this right but whatevs

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Answer:

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(B) 0.595

Step-by-step explanation:

Let,

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G = a person has the periodontal disease.

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(A)

The probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is:

$P(H|G)=\frac{P(G|H)P(H)}{P(G)}\\=\frac{0.79\times0.15}{0.399} \\=0.29699\\\approx0.297$

Thus, the probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is 0.297.

(B)

Now if the probability of a person having a heart attack is, P (H) = 0.38.

Compute the probability that a person has the periodontal disease as follows:

$P(G)=P(G|H)P(H)+P(G|H')P(H')\\=P(G|H)P(H)+P(G|H')(1-P(H))\\=(0.79\times0.38)+(0.33\times(1-0.38))\\=0.5048$

Compute the probability of a person having a heart attack given that he or she has the disease:

$P(H|G)=\frac{P(G|H)P(H)}{P(G)}\\=\frac{0.79\times0.38}{0.5048}\\ =0.59469\\\approx0.595$

The probability of a person having a heart attack given that he or she has the disease is 0.595.

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2 years ago

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