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Aleonysh [2.5K]
3 years ago
6

Suppose f(x) is a function such that if p f(x) can be odd or even. f(x) can be odd but cannot be even. f(x) can be even

but cannot be odd.
f(x) cannot be odd or even.
Mathematics
1 answer:
Ghella [55]3 years ago
5 0

Answer:

f(x) can be odd or even.

Step-by-step explanation:

The following information is missing in the question:

<em>Suppose f(x) is a function such that if p < q, f(p) < f(q). Which statement best describes f(x)? </em>

With the information given it is not possible to determine if the function is even or odd.

Even functions: f(-x) = f(x). For examle, (-2)² = 2², then x² is even

Odd functions: f(-x) = -f(x). For examle, (-2)³ = -(2³), then x³ is odd

In both cases, x² and x³, if p < q, f(p) < f(q). For example, 1² < 2², and 1³ < 2³

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Answer:

Confidence limit = [52.8%, 75.2%]

Step-by-step explanation:

P=\frac{45}{70}= 0.64

(1-P)=1-0.64=0.36

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P ± z \sqrt{\frac{P(1-P)}{n} }

where the value z will be taken from the z-table for 95% confidence interval

1-0.95= 0.05/2= 0.025

0.95+0.025= 0.0975

From the z-table the value of z corresponding to 0.0975 is 1.96

0.64 ± 1.96 \sqrt{\frac{0.64*0.36}{70} }

0.64 ± 1.96 (0.057)

0.64 ± 0.112

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so the confidence interval is

64+11.2=75.2%

64-11.2=52.8%

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3 years ago
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Scorpion4ik [409]

Answer:

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Step-by-step explanation:

Assuming that there's a typo in the question and that he made 57% of his attempted free throws, then we can solve it as shown below:

We can apply a rule of three in order to calculate the number of free throws he made. This is done as follows:

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It can also be solved by transforming the percentage in a fraction such as 57% = 57/100 and then multiplying it by the total attempts.

free throws made = 56*57/100 = 31.92

He made approximately 32 free throws.

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