Answer:
b. How many ways arc there to go 12 miles?
≡ p(12) = 25
c. How many ways arc there to go 20 miles?
≡ p(20) = 131
d. How many ways arc there to go 22 miles?
≡p(22) 199
Step-by-step explanation:
a) supposed you walked for the first hour. Then you would have travelled 3 miles. if you jogged you would have covered 5miles and if you run you would have covered 10miles. now you have to decide how to run the rest miles from the n miles.
Thus, the number of ways one can cover n miles will be given by the recurrence relation
p(n) = p( n-3) + p( n-5) + p( n - 10)
now to solve the rest of the question, let us make a table which provides the number of ways for n = 1 to 22.
check the attachment for the table
b. How many ways arc there to go 12 miles?
≡ p(12) = 25
c. How many ways arc there to go 20 miles?
≡ p(20) = 131
d. How many ways arc there to go 22 miles?
≡p(22) 199
Answer: each 1/3 would be 4 brownies.
Step-by-step explanation: 12 divided by 3 is 4.
1. Angles ADC and CDB are supplementary, thus
m∠ADC+m∠CDB=180°.
Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.
2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then
m∠CDB=m∠CBD=65°.
The sum of the measures of interior angles of triangle is 180°, therefore,
m∠CDB+m∠CBD+m∠BCD=180° and
m∠BCD=180°-65°-65°=50°.
3. Triangle ABC is isosceles, with base BC. Then
m∠ABC=m∠ACB.
From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So
m∠ACB=65°.
4. Angles BCD and DCA together form angle ACB. This gives you
m∠ACB=m∠ACD+m∠BCD,
m∠ACD=65°-50°=15°.
Answer: 15°.