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Georgia [21]
3 years ago
14

The difference of two odd numbers is always an odd number. true or false​

Mathematics
2 answers:
Neko [114]3 years ago
7 0

True.

The difference between an even and odd numbers always result in odd number

lions [1.4K]3 years ago
4 0

Answer:

?

Step-by-step explanation:

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A thin tube stretched across a street counts the number of pairs of wheels that pass over it. A vehicle classified as type A wit
aliina [53]

Answer: All possible solutions would be

(1,41), (8,33), (15,25), (22,17), (29,9), (36,1)

Step-by-step explanation:

Let the number of vehicle of type A be 'x'.

Let the number of vehicle of type B be 'y'.

Since we have given that

Number of axles of type A = 2

Number of axles of type B = 9

After 2 hours, number of counts = 101

so, our equation becomes,

2x+9y=101

So, all possible solutions would be

(1,41), (8,33), (15,25), (22,17), (29,9), (36,1)

7 0
3 years ago
What is the simplest form of this expression?<br> -(х – 2)(3х2 + 4х-5)
skad [1K]

Answer:

C

Step-by-step explanation:

3x^2 * -x =-3x^3

3x^2 * 2. =6x^2

4x* -x =-4x^2

4x * 2 = 8x

-5 * -x = 5x

-5 * 2 = -10

6x^2 + -4x^2 = 2x^2

8x+5x = 13 x

Ans: -3x^3 + 2x^2 + 13x -10

7 0
3 years ago
Read 2 more answers
Simplify the expression.<br>13[6^2/(5^2-4^2)+9]<br><br> 181<br><br> 169<br><br> 26<br><br> 585
Zina [86]
So 5^2 -4^2 is 25-16 which is 9
6^2/9 is 36/9 which is 4 +9 is 13
13(13) is 169
7 0
3 years ago
The half-life of Radium-226 is 1590 years. If a sample contains 200 mg, how many mg will remain after 1000 years?
adell [148]

Answer: 129.33 g

Step-by-step explanation:

$$Let $p=A \cdot e^{n t}$ \\$(p=$ present amount, $A=$ initial amount, $n=$ decay rate, $t=$ time)

\begin{aligned}&\Rightarrow \text { Given } p=\frac{A}{2} \ a t  \ t=1590 \\&\Rightarrow \frac{1}{2}=e^{1590n} \Rightarrow n=\frac{\ln (1 / 2)}{1590}=-0.00043594162\end{aligned}

$$If $A=200 \mathrm{mg}$ and $t=1000$ then,$$\begin{aligned}P &=200 e^{\left(\frac{\ln \left(1/2\right)}{1590}\right) \cdot 1000} \text \\\\&=129.33 \text { grams}\end{aligned}$$

3 0
2 years ago
At the beginning of a semester an anonymous survey was conducted on students in a statistics class. Two of the questions on the
kati45 [8]

Answer:

a. Chi-square test of independence

Step-by-step explanation:

The chi square statistics is also used to test the hypothesis about the independence of two variables each of which is classified into a number of categories or attributes.

In the given problem the Equal , more or less are the attributes.

The goodness of fit test is applicable when the cell probabilities depend upon the unknown parameters  provided that the unknown parameters are replaced with their estimates and provided that one degree of freedom is deducted for each parameter estimated.

4 0
3 years ago
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