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3 years ago

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The weight of a full steel bead tire is approximately 800

1 answer:

AleksAgata [21]3 years ago

5 0

Answer: 1.76

1.54

Step-by-step explanation:

we have to divide 800 by 453.592, and the result is 1.763699... rounding it: 1.76

now we do the same for 700 :

700 divided by 453.592 is 1.5432... so rounding it down: 1.54

You might be interested in

Test the claim that the mean GPA of night students is larger than 3.1 at the .10 significance level. The null and alternative hy

Alborosie

Answer:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

$df = n-1=75-1 =74$

The p value is:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is: 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

Step-by-step explanation:

For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

We have the following info given:

$\bar X = 3.13 , s =0.03 , n =75$

The statistic to check the hypothesis is given by:

$t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}$

Replacing the info given we got:

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

The degrees of freedom are given by:

$df = n-1=75-1 =74$

The p value since is a right tailed ted is given by:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

6 0

3 years ago

Elleanna is planning is join a DVD club and is investigating the options for membership.Option 1 is a $20 memership fee and $1.2

In-s [12.5K]

She would have to rent 2 movies.

1.25 x 2 = 2.50

7 0

3 years ago

A computer can sort x objects in t seconds, as modeled by the function

r-ruslan [8.4K]

Answer:

36 objects

Step-by-step explanation:

You want the value of x when t=9, so you're solving ...

9 = 0.007x^2 +0.003x

9 = 0.007(x^2 + 3/7x)

From here, we observe that an approximation is probably sufficient.

9/0.007 = x(x +3/7) . . . . . the expression on the right is nearly x^2

x ≈ 3/√.007 ≈ 35.9 ≈ 36

We can check:

.007(36)(36 3/7) = 9.18

.007(35)(35 3/7) = 8.68

To keep the computer busy for 9 seconds, it needs to sort 36 objects.

6 0

3 years ago

Please help need answers

bogdanovich [222]

see explanation below

(1) $\frac{1}{5}$ × $\frac{2}{2}$ = $\frac{2}{10}$ = 0.2

(2) $\frac{6}{25}$ × $\frac{4}{4}$ = $\frac{24}{100}$ = 0.24

(3) 2 $\frac{3}{4}$ = 2 + $\frac{75}{100}$ = 2.75

(4) 3 $\frac{9}{10}$ = 3 + 0.9 = 3.9

(5) 1.25 = 1 $\frac{1}{4}$ = $\frac{5}{4}$

(6) 3.29 = 3 $\frac{29}{100}$ = $\frac{329}{100}$

(7) 0.65 = $\frac{65}{100}$ = $\frac{13}{20}$ in simplest form

(8) 5.6 = 5 $\frac{6}{10}$ = 5 $\frac{3}{5}$ = $\frac{28}{5}$

(9) he is incorrect

$\frac{3}{5}$ × $\frac{20}{20}$ = $\frac{60}{100}$ = 0.6 ≠ 3.5

7 0

3 years ago

The 6 elephants at the zoo have a combined weight of 11,894 pounds. About how much does each elephant weigh?

Sidana [21]

Answer: 14,000 i think

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers