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3 years ago

PLEASE HELP FOR 20 POINTS

Mathematics

1 answer:

Furkat [3]3 years ago

8 0

Answer:

$15

Step-by-step explanation:

Let bushes = b and trees = t.

We can write:

12b + 15t = 600 (Equation 1)

8b + 20t = 680 (Equation 2)

24b + 30t = 1200 (Equation 3 -- Multiply Equation 1 by 2)

24b + 60t = 2040 (Equation 4 -- Multiply Equation 2 by 3)

30t = 840 (Subtract Equation 3 from 4)

t = 28 (Divide by 30)

12b + 15 * 28 = 600 (Substitute t = 28 into Equation 1)

12b = 180 (Simplify)

b = 15 (Divide by 12)

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Answer:

Step-by-step explanation:

Perimeter of a rectangle = 2(L +W)

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< 2(2W+2)

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3 years ago

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Artyom0805 [142]

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3 years ago

The total claim amount for a health insurance policy follows a distribution with density function 1 ( /1000) ( ) 1000 x fx e− =

gizmo_the_mogwai [7]

Answer:

the approximate probability that the insurance company will have claims exceeding the premiums collected is $\mathbf{P(X>1100n) = 0.158655}$

Step-by-step explanation:

The probability of the density function of the total claim amount for the health insurance policy is given as :

$f_x(x) = \dfrac{1}{1000}e^{\frac{-x}{1000}}, \ x> 0$

Thus, the expected total claim amount $\mu$ = 1000

The variance of the total claim amount $\sigma ^2 = 1000^2$

However; the premium for the policy is set at the expected total claim amount plus 100. i.e (1000+100) = 1100

To determine the approximate probability that the insurance company will have claims exceeding the premiums collected if 100 policies are sold; we have :

P(X > 1100 n )

where n = numbers of premium sold

$P (X> 1100n) = P (\dfrac{X - n \mu}{\sqrt{n \sigma ^2 }}> \dfrac{1100n - n \mu }{\sqrt{n \sigma^2}})$

$P(X>1100n) = P(Z> \dfrac{\sqrt{n}(1100-1000}{1000})$

$P(X>1100n) = P(Z> \dfrac{10*100}{1000})$

$P(X>1100n) = P(Z> 1) \\ \\ P(X>1100n) = 1-P ( Z \leq 1) \\ \\ P(X>1100n) =1- 0.841345$

$\mathbf{P(X>1100n) = 0.158655}$

Therefore: the approximate probability that the insurance company will have claims exceeding the premiums collected is $\mathbf{P(X>1100n) = 0.158655}$

4 0

2 years ago