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3 years ago

The image of the point (6, 6) under a translation is (5,2). Find the coordinates of

Mathematics

1 answer:

Dmitry [639]3 years ago

6 0

9514 1404 393

Answer:

(-1, -2)

Step-by-step explanation:

The difference between the coordinates of the image and the coordinates of the original is the same for both points.

X - (0, 2) = (5, 2) -(6, 6)

X = (5, 2) -(6, 6) +(0, 2) = (5-6+0, 2-6+2)

X = (-1, -2)

The image of the point after translation is (-1, -2).

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Bogdan [553]

Answer:

Option 2

Step-by-step explanation:

I say option to because it is 990

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3 years ago

56,426+17,895

pochemuha

Answer:

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Step-by-step explanation:

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3 years ago

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H=vt+1/2gt^2 solving for G <br>GIVING BRAINLISEST

ololo11 [35]

Answer:

$g=\frac{2h}{t^2}-\frac{2v}{t}$

Step-by-step explanation:

So we have the equation:

$h=vt+\frac{1}{2}gt^2$

And we want to solve for g.

First, isolate g. To do so, subtract vt from both sides:

$h-vt=\frac{1}{2}gt^2$

Multiply both sides by 2:

$2h-2vt=gt^2$

Now, divide both sides by t^2:

$g=\frac{2h-2vt}{t^2}$

Expand:

$g=\frac{2h}{t^2}-\frac{2vt}{t^2}$

Simplify the second term:

$g=\frac{2h}{t^2}-\frac{2v}{t}$

And we're done!

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2 years ago

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What is the enlargement ratio if you enlarge the figure to have a width of 16 units and length of 12 units

Fantom [35]

Answer:

The enlargement ratio is 3:4

Step-by-step explanation:

We are given

a width of 16 units and length of 12 units

so,

$W=16$

and

$L=12$

now, we can find enlargement ratio

we can use formula

enlargement ratio = (length)/(width)

$=\frac{L}{W}$

now, we can plug values

$=\frac{12}{16}$

now, we can simplify it

$=\frac{3}{4}$

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The enlargement ratio is 3:4

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3 years ago

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sveticcg [70]

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2 years ago