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Rama09 [41]
3 years ago
15

Y= x^2 + 2x + 7 in vertex form

Mathematics
2 answers:
Irina18 [472]3 years ago
5 0

Answer:

y = (x + 1)² + 6

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier.

To obtain this form use the method of completing the square

Given

y = x² + 2x + 7

add/subtract ( half the coefficient of the x- term )² to x² + 2x

y = x² + 2(1)x + 1 - 1 + 7

  = (x + 1)² + 6 ← in vertex form

Maslowich3 years ago
4 0

Answer:

( 1,  6 )

Step-by-step explanation:

y = (x − 1 ) 2 + 6

Use the vertex form,  y = a ( x − h ) 2 + k , to determine the values of a ,  h , and  k . a = 1 h = 1 k = 6

Find the vertex  ( h ,  k ) .  ( 1 ,  6)

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What two decimals are equivalent to 4.400
Zina [86]

Answer:

4.4

4.40

Step-by-step explanation:

These two decimals above are equivalent to 4.400 because no matter the amount of zeroes, the numbers are the same. For example, 4.400 is also equivalent to 4.400000000000000000000000000000000.  As long as the  "4's" maintain the same place (ones place and tens place), the decimals will be congruent to one another.

4 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST ANSWER THIS PLZ!
Nutka1998 [239]
The answer is b, tell me if you don't understand.
8 0
3 years ago
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Write and solve an inequality to find the values of x for which the perimeter of the rectangle is less than 120.
RSB [31]

Answer:

Inequality : 4x+8 < 120

x<28

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Perimeter of a rectangle (P)= 2 length +2 width

Where:

Width = x

Length = x+4

Replacing with the values given

P = 2 (x+4) + 2x

P = 2x+8+2x

P=4x+8

Since the perimeter of the rectangle must be less than 120:

4x+8 < 120

Solving for x

4x<120-8

4x<112

x<112/4

x<28

Feel free to ask for more if needed or if you did not understand something.  

4 0
3 years ago
12 2/5 - 4 4/6 in whole numbers &amp; fractions
Artist 52 [7]
12 2/5 - 4 4/6 = ?
Whole number: It cannot be a whole number, since it is a repeating decimal. As a repeating decimal, it is 7.7333333333333 and so on. If you round it to the ones place, it would become 8. As a simplified decimal, it would be 7.7

Fraction: 7 11/15

HOPE THIS HELPED. ;-)
6 0
3 years ago
A particle is moving along the x-axis so that its position at t ≥ 0 is given by s(t)=(t)ln(5t). Find the acceleration of the par
lyudmila [28]

Answer:

a(\frac{1}{5e})=5e

Step-by-step explanation:

we are given equation for position function as

s(t)=tln(5t)

Since, we have to find acceleration

For finding acceleration , we will find second derivative

s'(t)=\frac{d}{dt}\left(t\ln \left(5t\right)\right)

=\frac{d}{dt}\left(t\right)\ln \left(5t\right)+\frac{d}{dt}\left(\ln \left(5t\right)\right)t

=1\cdot \ln \left(5t\right)+\frac{1}{t}t

s'(t)=\ln \left(5t\right)+1

now, we can find derivative again

s''(t)=\frac{d}{dt}\left(\ln \left(5t\right)+1\right)

=\frac{d}{dt}\left(\ln \left(5t\right)\right)+\frac{d}{dt}\left(1\right)

=\frac{1}{t}+0

a(t)=\frac{1}{t}

Firstly, we will set velocity =0

and then we can solve for t

v(t)=s'(t)=\ln \left(5t\right)+1=0

we get

t=\frac{1}{5e}

now, we can plug that into acceleration

and we get

a(\frac{1}{5e})=\frac{1}{\frac{1}{5e}}

a(\frac{1}{5e})=5e


5 0
3 years ago
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