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umka21 [38]
3 years ago
15

a triangular flower bed needs a thin metal border all the way around it. The sides are 7 feet, 6 feet, and 9 feet long.

Mathematics
1 answer:
kotegsom [21]3 years ago
7 0
Excuse my awful triangle drawing skills, haha..
So essentially you need to find the perimeter which is done by adding the lengths of the sides.. this gives you 22ft.
Then for part b you need to convert 22ft to yards which gives you 7.3 yards.
Since you can only buy a whole number of yards, you'll actually need 8 yards.
So if the boarder is $8.75 per yard, and you need 8 yards, how much would it cost?
Hope this was helpful.

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Miguel sells insurance. He earns a 6% commission on each sale he makes. Miguel has a goal of earning $600 in commissions. Miguel
WARRIOR [948]

Answer:

$564

Step-by-step explanation:

6% of 600 is 36

So 600-36= $564

7 0
3 years ago
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What is the line slope of (10,5) and (1,9)
sveta [45]
Use the slope formula
y2-y1
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Hope that helped :-)
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Garth estimated the height of the door ti his classroom in meters. what is a reasonable estimate?
chubhunter [2.5K]
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7 0
3 years ago
Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and
zzz [600]

Answer:

\bold{sin(38^\circ)=cos(52^\circ)}

Step-by-step explanation:

Given that \triangle KJL is a right angled triangle.

\angle JKL = 52^\circ\\\angle KLJ = 38^\circ

and

\angle KJL = 90^\circ

Kindly refer to the attached image of \triangle KJL in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given \triangle KJL.

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

sin\theta =\dfrac{Perpendicular}{Hypotenuse}

sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

cos\theta =\dfrac{Base}{Hypotenuse}

cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}....... (2)

By (1) and (2):

sin(38°) \neq cos(38°).

cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL} ...... (3)

Comparing equations (1) and (3):

we get the both are same.

\therefore \bold{sin(38^\circ)=cos(52^\circ)}

6 0
3 years ago
What is 3.06 rounded each number to the nearest tenths?
g100num [7]
3.1
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6 0
3 years ago
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