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Lesechka [4]
3 years ago
5

How to use. Rounding when estimating

Mathematics
1 answer:
Lina20 [59]3 years ago
4 0
You just round the numbers
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Jasmine wants to build a 2 5/6 meter long garden path paved with square stones that measure 1/4 meter on each side. There will b
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23 stones are going to be needed

Step-by-step explanation:

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Find all sets of four consecutive integers whose sum is between 95 and 105
Nat2105 [25]
Hello,

Let n-2,n-1,n,n+1 the foru numbers
s=n-2+n-1+n+n+1=4n-2

95<=4n-2<=105
==>97<=7n<=107
==>24.25<=n<=26.75
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7 0
3 years ago
the sum of two consecutive integers is -49 write an equation that models this situation and find the values of the two integers
hodyreva [135]
Х is the first <span>integer
</span>(x+1) is the second integer

x + x + 1 = -49
2x + 1 = - 49
2x = -49 - 1
2x = -50
x = -25  first integer
-25 + 1 = -24 second integer

Answer: -25 and -24
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3 years ago
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Below is a probability distribution for the number of failures in an elementary statistics course. X 0 1 2 3 4 P(X=x) 0.41 0.18
faust18 [17]

Answer:

a) P(X=2)= 0.29

b) P(X<2)= 0.59

c) P(X≤2)= 0.88

d) P(X>2)= 0.12

e) P(X=1 or X=4)= 0.24

f) P(1≤X≤4)= 0.59

Step-by-step explanation:

a) P(X=2)= 1 - P(X=0) - P(X=1) - P(X=3) - P(X=4)= 1-0.41-0.18-0.06-0.06= 0.29

b) P(X<2)= P(X=0) + P(X=1)= 0.41 + 0.18 = 0.59

c) P(X≤2)= P(X=0) + P(X=1) + P(X=2)=0.41+0.18+0.29= 0.88

d) P(X>2)=P(X=3) + P(X=4)=0.06+0.06= 0.12

e) P(X=1 or X=4)=P(X=1 ∪ X=4) = P(X=1) + P(X=4)=0.18+0.06= 0.24

f) P(1≤X≤4)=P(X=1) + P(X=2) + P(X=3) + P(X=4)=0.18+0.29+0.06+0.06= 0.59

3 0
3 years ago
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