For the first line we have a slope of (y2-y1)/(x2-x1)
(2--2)/(1--1)=4/2=2 so we have:
y=2x+b, now solve for b with either of the points, I'll use: (1,2)
2=2(1)+b
b=0 so the first line is:
y=2x
Now the second line:
(1-10)/(4--2)=-9/6=-3/2 so far then we have:
y=-3x/2+b, using point (4,1) we solve for b...
1=-3(4)/2+b
1=-6+b
b=7 so
y=-3x/2+7 or more neatly...
y=(-3x+14)/2
...
The solution occurs when both the x and y coordinates for each are equal, so we can say y=y, and use our two line equations...
2x=(-3x+14)/2
4x=-3x+14
7x=14
x=2, and using y=2x we see that:
y=2(2)=4, so the solution occurs at the point:
(2,4)
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Do you notice anything strange about those points ?
(0, 1),
(1, 2),
(2, 4),
(3, 8).
The y-coordinate of each point is (2) raised to the power of the x-coordinate.
First point: x=0, y=2⁰ = 1
Second point: x=1, y=2¹ = 2
Third point: x=2, y=2² = 4
Fourth point: x=3, y=2³ = 8
The equation of the curve appears to be
y = 2 ^ x .
So, after 10 hours, x=10, and y = 2¹⁰ = 1,024 .
Answer:
Step-by-step explanation:
domain is all ur x values.....
domain = { -4,0,2,3}....u only have to write them once if they repeat
range is all ur y values....
range = { 0,1,4,5}
