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AlekseyPX
3 years ago
9

Many and his friends were comparing how much each of them grew last year. many grew 4 inches. jeff grew 1 1/2' times that amount

. allison grew 4/4 as much. sarah 3/5 as much. put the students in order of how much they grew last year from greatest to least ?
Mathematics
2 answers:
7nadin3 [17]3 years ago
6 0
I placed them from least to greatest
Sarah- 3/5x4= 2.4 inch
Many- 4 inch
Allison 4/4=1 (as much) which mean the same as Many= 4 inch
Jeff 4 x 1 1/2=6 inch
lukranit [14]3 years ago
3 0
Jeff=6 inches
Allison=4 inches
Sarah=2.4 inches
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Suppose the roots of the polynomial $x^2 - mx + n$ are positive prime integers (not necessarily distinct). Given that $m < 20
Vsevolod [243]

Answer:

<em>18</em> values for n are possible.

Step-by-step explanation:

Given the quadratic polynomial:

$x^2 - mx + n$

such that:

Roots are positive prime integers and

$m < 20$

To find:

How many possible values of n are there ?

Solution:

First of all, let us have a look at the sum and product of a quadratic equation.

If the quadratic equation is:

Ax^{2} +Bx+C

and the roots are: \alpha and \beta

Then sum of roots, \alpha+\beta = -\frac{B}{A}

Product of roots, \alpha \beta = \frac{C}{A}

Comparing the given equation with standard equation, we get:

A = 1, B = -m and C = n

Sum of roots,  \alpha+\beta = -\frac{-m}{1} = m

Product of roots, \alpha \beta = \frac{n}{1} = n

We are given that m  

\alpha and \beta are positive prime integers such that their sum is less than 20.

Let us have a look at some of the positive prime integers:

2, 3, 5, 7, 11, 13, 17, 23, 29, .....

Now, we have to choose two such prime integers from above list such that their sum is less than 20 and the roots can be repetitive as well.

So, possible combinations and possible value of n (= \alpha \times \beta) are:

1.\ 2,  2\Rightarrow  n = 2\times 2 = 4\\2.\ 2, 3 \Rightarrow  n = 6\\3.\ 2, 5 \Rightarrow  n = 10\\4.\ 2,  7\Rightarrow  n = 14\\5.\ 2, 11 \Rightarrow  n = 22\\6.\ 2, 13 \Rightarrow  n = 26\\7.\ 2, 17 \Rightarrow  n = 34\\8.\ 3,  3\Rightarrow  n = 3\times 3 = 9\\9.\ 3, 5 \Rightarrow  n = 15\\10.\ 3, 7 \Rightarrow  n = 21\\

11.\ 3,  11\Rightarrow  n = 33\\12.\ 3, 13 \Rightarrow  n = 39\\13.\ 5, 5 \Rightarrow  n = 25\\14.\ 5, 7 \Rightarrow  n = 35\\15.\ 5, 11 \Rightarrow  n = 55\\16.\ 5, 13 \Rightarrow  n = 65\\17.\ 7, 7 \Rightarrow  n = 49\\18.\ 7, 11 \Rightarrow  n = 77

So,as shown above <em>18 values for n are possible.</em>

3 0
3 years ago
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expeople1 [14]

Answer:

First Number: 2

Step-by-step explanation:

You need to work backwards, as an algebraic equation.

24 ÷ 3 = 8

8 ÷ 2 = 4

4 × 2 = 8

8 - 6 = 2

The first number is 2.

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

Alrighty, what have we here: an area of 162 m² and a width of 9m.

So: A=162m², W=9m, let's draw this: (see the screenshot attached)

Using the formula for area (Area = width x length) we see that:

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Thus: (equating to L by dividing both sides by 9m)

⇒ \frac{162m^{2} }{9m}=18m=L

Now we have all of our dimensions, we can use the formula for the perimeter to calculate it:

perimeter=2W+2L=2*9m+2*18m=18m+36m=54m

And there we have our answer.

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