The factors of a polynomial function are the zeros of the function
It is true that x - 3 is a factor of m(x) = x^3 - x^2 - 5x - 3
<h3>How to show why the x - 3 is a factor</h3>
The function is given as:
m(x) = x^3 - x^2 - 5x - 3
The factor is given as:
x - 3
Set the factor to 0
x - 3 = 0
Solve for x
x = 3
Substitute 3 for x in the function
m(3) = 3^3 - 3^2 - 5(3) - 3
Evaluate
m(3) =0
Since the value of m(3) is 0, then x - 3 is a factor of m(x) = x^3 - x^2 - 5x - 3
Read more about factors at:
brainly.com/question/11579257
Answer:
Though, there is no given value of G.
The graph would look something like this.
<em>This </em><em>graph </em><em>was </em><em>made </em><em>with </em><em>an </em><em>F </em><em>value </em><em>of </em><em>1</em><em>.</em>
Step-by-step explanation:
None
Answer:

Step-by-step explanation:

Switching x variable with -2.

Evaluating.


Answer:
a = 16
Step-by-step explanation:
24:8 is the ratio
simplify into 3:8
6 ÷ 3 = 2
multiply the ratio by 2 to get a=16