Write the slope-intercept form of the equation for the line.

Please help ASAP! The terminal side of an angle θ in standard position passes through the point (2,-5). calculate the values of

Troyanec [42]

Answer:

$sin(x)=\frac{opp}{hyp}=\frac{5}{\sqrt{21}}=\frac{5\sqrt{21}}{21}\\cos(x)=\frac{adj}{hyp}=\frac{2}{\sqrt{21}}=\frac{2\sqrt{21}}{21}\\tan(x)=\frac{opp}{adj}=\frac{5}{2}\\csc(x)=\frac{hyp}{opp}=\frac{\sqrt{21}}{5}\\sec(x)=\frac{hyp}{adj}=\frac{\sqrt{21}}{2}\\cot(x)=\frac{adj}{opp}=\frac{2}{5}$

Step-by-step explanation:

Start by drawing out the triangle on the graph:

(See picture)

(By the drawing you can judge me that I am a really bad artist)

Theta and the side lengths are labeled, the hypotenuse has a length of √21 by Pythagora's theorem. Now, time to put everything to the trigonometric functions:

$sin(x)=\frac{opp}{hyp}=\frac{5}{\sqrt{21}}=\frac{5\sqrt{21}}{21}\\cos(x)=\frac{adj}{hyp}=\frac{2}{\sqrt{21}}=\frac{2\sqrt{21}}{21}\\tan(x)=\frac{opp}{adj}=\frac{5}{2}\\csc(x)=\frac{hyp}{opp}=\frac{\sqrt{21}}{5}\\sec(x)=\frac{hyp}{adj}=\frac{\sqrt{21}}{2}\\cot(x)=\frac{adj}{opp}=\frac{2}{5}$

(Suppose that x is theta as I can't type it)

By some basic understanding that's all that I can do.

3 0

2 years ago

The cost of 5 cans of dog food is 4.35. At this price ,how much do 11 cans of dog food cost

Setler [38]

Answer:

$9.57

Step-by-step explanation:

You have to do 4.35 divided by 5 to get how much 1 can cost. You will find out that 1 can cost $0.87. Next you will take how much one cost and mutiply it by 11. When you do that you will get 9.57. That is how you will get $9.57 as your answer.

5 0

3 years ago

What is 7<br> and 8 and 9

Roman55 [17]

7. 2/3
8. 8/9
9 2

I hope this helps
6 7
x 42/63 and simply which gets you 2/3
7 9

3 0

3 years ago

DAILY PRACTIC

ella [17]

Answer:

yo what?

Step-by-step explanation:

the health is this you awnser le ? I uh what?

6 0

3 years ago

I dont know how to find the orthocenter

AlladinOne [14]

Answer:

O = (3,3)

Explanation:

The <em>altitude</em> of a triangle is the perpendicular from a vertex to the opposite side.

The orthocentre (O) of a triangle is the point where the three vertices intersect.

We must find the equations for only two of the altitudes, because the third will also intersect at that point.

===============

Your three points make a right triangle.

The altitude of B is side AC.

The altitude of C is sde AB.

Their point of intersection at A (3,3) is the orthocentre of thetriangle.

4 0

3 years ago