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I am Lyosha [343]
3 years ago
14

#17: If the area of a rectangle measures 20 square inches, the side lengths must

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
4 0
A counterexample could be 2 inches and 10 inches.
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What is the greatest common factor (GCF) of 15 and 64? <br>1. (3) <br>2.(4)<br>3.(8)<br>4.(1)​
omeli [17]
It’s 1.

Explanation: you need to find the greatest factor that works out for them both. You can cross out 4 and 8 because no other whole number can be multiplied to get 15, and it’s not 3 since you can’t multiply it with a whole number to get 64. 1 works for them both.
4 0
3 years ago
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A biology class examined some flowers in a local meadow. The students saw 88 perennial
dezoksy [38]

Answer:

88%

Step-by-step explanation:

3 0
3 years ago
Gerard bought 9 hamburgers and 3 orders of fries for 24.75. Chris bought 6 hamburgers and 4 orders of fries for 19.50. Each hamb
dezoksy [38]
<span>9 hamburgers and 3 fries for 24.75 and 6 hamburgers and 4 fries for 19.50 can be represented by 9h + 3f = 24.75 and 6h + 4f = 19.5 Multiply by 4 36h + 12f = 99 and multiply by -3 -18h -12f = -58.5 12f and -12f cancel each other out 36h - 18h = 99 -58.5 18h = 40.5 h = 2.25 hamburgers cost 2.25 9h + 3f = 24.75 9(2.25) + 3f = 24.75 3f = 24.75 - 20.25 = 4.50 f = 150 fries cost 1.50 One hamburger and one fries can be represented by : h + f 2.25 + 150 = 3.75</span>
8 0
3 years ago
Simplify the expression.<br><br> [(11 - 4)^3]^2 ÷ (4 + 3)^5
MAXImum [283]

Answer:

<h2>7</h2>

Step-by-step explanation:

\left[\left(11\:-\:4\right)^3\right]^2\:\div \left(4\:+\:3\right)^5\\\\\frac{\left(\left(11-4\right)^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Subtract\:the\:numbers:}\:11-4=7\\\\=\frac{\left(7^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Add\:the\:numbers:}\:4+3=7\\\\=\frac{\left(7^3\right)^2}{7^5}\\\\\left(7^3\right)^2=7^6\\\\=\frac{7^6}{7^5}\\\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}\\\\\frac{7^6}{7^5}=7^{6-5}\\\\\mathrm{Subtract\:the\:numbers:}\:6-5=1\\\\=7

5 0
3 years ago
Please help
Varvara68 [4.7K]

Answer:

$6 = cost of small box

$8 = cost of large box

Step-by-step explanation:

Let s = cost of small box

     l  = cost of large box

(1)    12s + 3l = 96            (2)     6s + 6l = 84

    Multiply by -2                    <u> -24s - 6l = -192</u>

                                                -18s   = - 108

                                                     s = $6 = cost of small box

      12(6) + 3l = 96

         72 + 3l = 96

                 3l = 24

                   l = $8 = cost of large box

7 0
3 years ago
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