How do you collect and distribute this?

Which is 2.7084 rounded to the nearest tenth?

ehidna [41]

The tenth place is where the 7 is.

0.7

If the number behind it is over 5, we round up. If it isn't, we round down.

0<5

We round down.

2.7 is the answer.

I hope this helps!
~kaikers

4 0

2 years ago

Plz help ASAP!! Explain your answer! I will mark at brainliest!!! And don’t copy anybody else’s answer

Klio2033 [76]

Answer:

No, it is not a square

Step-by-step explanation:

If one wall is 19", that would mean the wall perpendicular to this wall is also 19" (in fact all of the walls would be 19"!) If this was a square, then the diagonal we draw at 20.62" would serve as the hypotenuse of a right triangle. One wall would serve as a leg, and another wall as another leg. If this is a square, then the Pythagorean's Theorem would be satisfied when we plug in the 2 wall measures for a and b, and the diagonal for c:

$19^2+19^2=20.62^2$

We need to see if this is a true statement. If the left side equals the right side, then the 2 legs of the right triangle are the same length, and the room, then is a square.

361 + 361 = 425.1844

Is this true? Does 722 = 425.1844? Definitely not. That means that the room is not a square.

8 0

2 years ago

A decorative window is made up of a rectangle with semicircles at either end. The ratio of AD to AB is 3:2 and AB is 30 inches.

scZoUnD [109]

Answer: The required ratio will be

$84:1034$

Step-by-step explanation:

Since we have given that

Ratio of AD to AB is 3:2

Length of AB = 30 inches

So, it becomes

$2x=30\\\\x=\frac{30}{2}=15\ inches$

So, Length of AD becomes

$3x=3\times 15=45\ inches$

Now, at either end , there is a semicircle.

Radius of semicircle along AB is given by

$\frac{30}{2}=15\ inches$

So, Area of semicircle along AB and CD is given by

$2\times \frac{\pi r^2}{2}\\\\=\frac{22}{7}\times 15\times 15\\\\=\frac{4950}{7}\ in^2$

Radius of semicircle along AD is given by

$\frac{45}{2}=22.5\ inches$

Area of semicircle along AD and BC is given by

$2\times \frac{1}{2}\pi r^2\\\\=\frac{22}{7}\times \frac{45}{2}\times \frac{45}{2}\\\\=\frac{445500}{28}\ in^2$

And the combined area of the semicircles is given by

$\frac{4950}{7}+\frac{445500}{28}\\\\=\frac{465300}{28}\ in^2$

Area of rectangle is given by

$Length\times width\\\\=AD\times AB\\\\=45\times 30\\\\=1350\ in^2$

Hence, Ratio of the area of the rectangle to the combined area of the semicircles is given by

$1350:\frac{465300}{28}\\\\=1350\times 28:465300\\\\=37800:465300\\\\=84:1034$

Hence, the required ratio will be

$84:1034$

8 0

2 years ago

Mr. D'Angelo hired a painter to paint the outside of his house green. The painter must mix 3 gallons of blue paint with every 5

Alborosie

Answer:

$\frac{3}{5}$

Step-by-step explanation:

3 gallons of blue paint and 5 gallons of yellow paint and this answer is a fraction so $\frac{3}{5}$ is the answer.

5 0

2 years ago

Joy is making a fruit salad. For every 2 cups of blueberries that Joy uses in the fruit salad, she uses 3 cups of strawberries.

Igoryamba

Joy will need to use 9 cups of strawberries for 6 cups of blueberries.

Step-by-step explanation:

Given,

Cups of blueberries used for 3 cups of strawberry = 2

Ratio of cups of blueberry to strawberry = 2:3

Joy wants to use 6 cups of blueberries.

Let,

x be the cups of strawberry for 6 cups of blueberries.

Ratio of cups of blueberries to strawberries = 6:x

Using proportion;

Ratio of cups of blueberry to strawberry :: Ratio of cups of blueberries to strawberries

$2:3::6:x$

Product of extreme = Product of mean

$2*x=3*6\\2x=18$

Dividing both sides by 2

$\frac{2x}{2}=\frac{18}{2}\\x=9$

Joy will need to use 9 cups of strawberries for 6 cups of blueberries.

Keywords: ratio, proportion, division

Learn more about division at:

#LearnwithBrainly

7 0

2 years ago