The approximate area of the triangular base of James’ tank is 3025 in²
To find the approximate area of the triangular base of James' tank, we need to know what scale is.
<h3>What is scale?</h3>
A scale is the ratio of two dimension. It is given by scale = New dimension/old dimension
Given that the dimensions of James’ tank are each exactly 2 3/4 times the dimensions of Julian’s tank.
The scale of the area of James' tank to the area of triangular base of Julian's tank is S = (2³/₄)²
= (11/4)²
= 121/16
Let
- A = area of triangular base of James' tank,
- A' = area of triangular base of Julian's tank = 400 in²
So, scale, S = A/A'
<h3>
The approximate area of the triangular base of James’ tank</h3>
So, making A subject of the formula, we have
A = SA'
A = 121/16 × 400 in²
A = 121 × 25 in²
A = 3025 in²
So, the approximate area of the triangular base of James’ tank is 3025 in²
Learn more about area of triangle here:
brainly.com/question/27436493
#SPJ1
Answer:
Camille did it right.
Step-by-step explanation:
4x-2y=8
Charlize: | Camille:
-2y=8+4x | -2y=8-4x
y=-4-2x | y=-4+2x
The right answer:
4x-2y=8
+2y +2y
4x=8+2y
-8 -8
2y=4x-8
2y/2=4x/2-8/2
y=2x-4 or y=-4+2x
So Camille is right, because she got y=-4+2x.
Answer:
5 up and 2 to the right
Step-by-step explanation:
The center will be at the same spot as circle D, dilate by 3, then the dilation maps circle C into circle D.
Answer:
A) 
Step-by-step explanation:
16+36=
or 
