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Flura [38]
3 years ago
11

Solve each system by substitution Y=6x-11 -2x-3y=-7

Mathematics
1 answer:
algol [13]3 years ago
4 0
You just plug in what Y equals into the second equation:
-2x-3(6x-11) = -7
then you solve the equation:
-2x-18x+33 = -7
-20x+33 = -7
subtract 33 from each side:
-20x = -40
divide each side by -20
x = 2
then you plug x into the original equation:
y = 6(2)-11
y = 12-11
y = 1
so x = 2 and y = 1
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