The number of students that are on the track team are 18.
The number of students that are on the baseball team are 15.
<h3>What are the linear equations that represent the question?</h3>
a + b = 33 equation 1
a - b = 3 equation 2
Where:
- a = number of students that are on the track team
- b = number of students that are on the baseball team
<h3>How many
students that are on the
baseball team?</h3>
Subtract equation 2 from equation 1
2b = 30
Divide both sides by 2
b = 30/2 = 15
<h3>How many
students that are on the track
team?</h3>
Subtract 15 from 33: 33 - 15 = 18
To learn more about simultaneous equations, please check: brainly.com/question/25875552
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Answer: 8 and 9 or -9 and -8
Step-by-step explanation:
Let 
be the first of the two integers. Then, since the numbers are consecutive, 
is the other integer. We then know that the sum of the squares of 
and is equal to 145. So, now we have the equation
which can be expanded and simplified to
which then gives us the quadratic equation
This can then be factored into
Which can be simplified further into
So either 
or 
. This gives us two solutions: 8 and 9 or -9 and -8.
Hope this helps! CHEERS!
A19 = -92
a20 = 6
common difference = d = a20 - a19
d = 6 - (-92)
d = 6 + 92
d = 98
formula for nth term
an = a1 + (n-1)d
put n = 20
a20 = a1 + (20-1)d
6 = a1 + 19(98)
6 = a1 + 1862
6 - 1862 = a1
-1856 = a1
a1 = -1856
now nth term:
an = a1 + (n-1)d
an = -1856 + (n-1)98
an = -1856 + 98(n-1)
