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ikadub [295]
2 years ago
9

Is 6/6 more than 3/3

Mathematics
1 answer:
hodyreva [135]2 years ago
4 0
They are both equivalent to 1, so they are equal. 

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8 cm<br> 5 cm<br> 10 cm<br> 12 cm
lana66690 [7]

Answer:

35 cm

Step-by-step explanation:

6 0
2 years ago
Solve this quadratic equation by completing the square. x2 + 10x = 26
Misha Larkins [42]
                        x² + 10x = 26
                x² + 10x + 25 = 26 + 25
          x² + 5x + 5x + 25 = 51
x(x) + x(5) + 5(x) + 5(5) = 51
         x(x + 5) + 5(x + 5) = 51
                 (x + 5)(x + 5) = 51
                          (x + 5)² = 51
                             x + 5 = ±√(51)
                                 - 5      - 5
                                   x = -5 ± √(51)
                                   x = -5 + √(51)    or    x = -5 - √(51)
5 0
3 years ago
Read 2 more answers
A pound of chocolate costs 8 dollars. Ann buys p pounds. Write an equation to represent the total cost c that Ann pay
aleksandrvk [35]

Answer:

Since it is 6 dollars per pound, his total cost c is 6 times p...thus

c = 6p

Hope this helps and hopefully I can get brainliest.

5 0
3 years ago
Model how to factor the polynomial 2x^3-8x^2+3x-12
san4es73 [151]
2x^3-8x^2+3x-12=2x^2(x -4)+3(x -4)=(x -4)(2x^2+3)


6 0
3 years ago
The cost of riding in a cab is $3.00 plus $0.75 per mile. The equation that represents this relation is y = 0.75x +3, where x is
Gemiola [76]

Answer:

Yes, the relation is a function.

Step-by-step explanation:

Given:

The equation that represents the cost of riding a cab is given as:

y=0.75x+3

Where, 'x' is the number of miles traveled and 'y' is the the total cost of the trip.

The above equation represents a line as it is of the form y=mx+b which represents a line with constant slope.

Now, in order to plot this equation, we need at least two points.

Now, let x =0, then

y=0.75(0)+3=3. So, (0, 3) is a point on the line.

Let x =1, then

y=0.75(1)+3=3.75. So, (1, 3.75) is a point on the line.

Plot these two points on a graph and draw a line passing through these two points.

Now, for a relation to be a function, it should pass the vertical line test.

According to vertical line test, vertical lines passing through the graph must cut the graph at only 1 point for the graph to represent a function.

Here, we observe that vertical lines passing through the line will intersect the line only at one point. So, it represent a function.

8 0
3 years ago
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