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ikadub [295]
3 years ago
9

Is 6/6 more than 3/3

Mathematics
1 answer:
hodyreva [135]3 years ago
4 0
They are both equivalent to 1, so they are equal. 

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in a change jar, tom has nickels and dimes. the number of nickels is two times the number of dimes and the total amount of money
AleksAgata [21]
N=number of nickles
d=number of dimes

n is 2 times d
n=2d
total money is 1.20
convert to cens
120 cetns

5n+10d=120
n=2d
5(2d)+10d=120
10d+10d=120
20d=120
divide both sides by 120
d=6
6 dimes is answer

answer is A, 6 dimes
8 0
3 years ago
A transportation agency has one 37-seater bus and some 12-seater buses. They have enough seats to board no more than 435 passeng
Ahat [919]

Answer:

I think its D

Step-by-step explanation:

8 0
3 years ago
To raise money for a local charity, students organized a wake-a-thon
arsen [322]

Answer:

a) T= 3.125h

b) $75

Step-by-step explanation:

Given: We know Tania raised $50 for staying awake 16 hours. We also know the amount of money raised varies directly with the time.

We can divide $50 into 16 hours.

50/16 = 25/8

25/8 = 3.125

3.125 = 3 1/8 (You can use a fraction or decimal, whichever is preferred)

That's how much money she earns per hour. It may not make sense because you have 1/8 of a dollar, so it's okay if you're a little confused on that.

Now let's answer the first question: Write an equation relating the money Tania raised and the  amount of time, in hours, she stayed awake.

We know Tania earns $3.125 per hour, so we can make it this equation

T= 3.125h

T can represent Tania's earnings, and 3.125 is how much she earns h, hourly.

Now onto the second question: How much would she have raised by staying awake for 24 h?

We need to multiply 3.125, or 3 1/8, 24 times. Your answer should be $75.

(I apologize in advance if I misread something or made a mistake)

6 0
3 years ago
Jacob bought a magazine for $2.80 and three candy bars. Write an expression for how much Jacob paid.
harkovskaia [24]

Answer:

total = 2.8 + 3x

x is the price of the candy bars

4 0
3 years ago
How to do this question by proving the identity?
jeyben [28]

\sin^3 \theta-\cos^3 \theta=(\sin \theta-\cos \theta)(\sin \theta\cos \theta+1)\\\\
(\sin \theta-\cos \theta)(\sin^2 \theta+\sin \theta\cos \theta +\cos^2 \theta)=(\sin \theta-\cos \theta)(\sin \theta\cos \theta+1)\\\\
(\sin \theta-\cos \theta)(\sin \theta\cos \theta+1)=(\sin \theta-\cos \theta)(\sin \theta\cos \theta+1)\\\\

6 0
4 years ago
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