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3 years ago

Please help. Look at screenshot

Mathematics

1 answer:

Vsevolod [243]3 years ago

6 0

Answer:

a. The function is increasing when $x>4$ and decreasing when $x$ .

b. The function is greater than zero when $x$ and $x>5$

c. The function is less than zero when $3$

Step-by-step explanation:

a. The function $f(x)$ is increasing when it's instantaneous slope ( the slope of the line tangent to the graph ) is positive, and it is decreasing when the instantaneous slope is negative. We see from the graph of $f(x)$ that for $x>4$ the instantaneous slope is positive, and for $x$ the slope is negative.

b. From the graph we see that the function is greater the zero (has positive values ) when $x$ and $x>5$ .

c. The graph of the function is less than zero ( is negative) when $3$

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Rent and other associated housing costs, such as utilities, are an important part of the estimated costs of attendance at colleg

Anton [14]

Answer: $(336.49,\ 355.51)$

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

Given : Sample size : $n= 314$ , which is a large sample , so we apply z-test .

Sample mean : $\overline{x}=346$

Standard deviation : $\sigma= 86$

Significance level : $\alpha=1-0.95=0.05$

Critical value : $z_{\alpha/2}=1.96$

Now, a confidence interval at the 95% level of confidence will be :-

$346\pm(1.96)\dfrac{86}{\sqrt{314}}\\\\\approx346\pm9.51\\\\=(346-9.51,\ 346+9.51)\\\\=(336.49,\ 355.51)$

8 0

3 years ago

Use the X method to find the solutions of 6x2 + 2x – 20 = 0.

Keith_Richards [23]

Answer:Hopes this helps!

6x²+2x-20=0

==>6x²+12x-10x-20=0

==>6x(x+2)-10(x+2)=0

==>(x+2)(6x-10)=0

==>x=-2 or x=5/3

5 0

3 years ago

Read 2 more answers

Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based

Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for $\mathrm{sinc}\,x$ about $x=0$ :

$\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}$

Then the Taylor series for

$f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt$

is obtained by integrating the series above:

$f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

We have $f(0)=0$ , so $C=0$ and so

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

which converges by the ratio test if the following limit is less than 1:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}$

Like in the linked problem, the limit is 0 so the series for $f(x)$ converges everywhere.

7 0

3 years ago

X÷2+4 greater than 7

denpristay [2]

I’m am almost sure it’s true it should look like this X
__ > 7
2+4

8 0

4 years ago

What is the equation of the line shown in this graph? any links will be reported

Blizzard [7]

Answer:

y = 1

Step-by-step explanation:

Slope is written in the form y=mx+b. Where m is the slope and b is the y-intercept.

When there isn't a slope, as in the line is flat and it isn't moving up or down, you wouldn't write anything for it. You would just write y equals the y-intercept (y = b).

Likewise, if the y-intercept is at (0,0), then you'd only write y equals the slope (y = mx).

Hopefully this makes sense :)

Btw, I also answered in the main comments earlier, so you can check that out as well.

7 0

3 years ago