Please help. Look at screenshot
1 answer:
Answer:
a. The function is increasing when and decreasing when
.
b. The function is greater than zero when and
c. The function is less than zero when
Step-by-step explanation:
a. The function is increasing when it's instantaneous slope ( the slope of the line tangent to the graph ) is positive, and it is decreasing when the instantaneous slope is negative. We see from the graph of
that for
the instantaneous slope is positive, and for
the slope is negative.
b. From the graph we see that the function is greater the zero (has positive values ) when and
.
c. The graph of the function is less than zero ( is negative) when
You might be interested in
The perimeter of right isosceles ΔABC with midsegment DE is 16 + 8√2.
If right isosceles ΔABC has hypotenuse length h, then the two other sides are congruent.
side a = side b
Using Pythagorean theorem, c^2 = a^2 + b^2
h^2 = a^2 + b^2 a = b
h^2 = 2a^2
a = h/√2
If DE is a midsegment not parallel to the hypotenuse, then it is a segment that connects the midpoints of one side of a triangle and the hypotenuse. See photo for reference.
ΔABC and ΔADE are similar triangles.
a : b : h = a/2 : 4 : h/2
If a/2 = a/2, then b/2 = 4.
b/2 = 4
b = 8
If a = b, then a = 8.
If a = h/√2, then
8 = h/√2
h = 8√2
Solving for the perimeter,
P = a + b + h
P = 8 + 8 + 8√2
P = 16 + 8√2
P = 27.3137085
To learn more about midsegment: brainly.com/question/7423948
#SPJ4
