THIS IS A RIGHT & isosceles triangle: A = 90. B = 45 THEN ANGLE C =45
THEN AB = AC = 4√2
APPLY PYTHAGORAS: BC² =AB² + AC²
===> X² = (4√2)² + (4√2)² ==>16.2 +16.2 = 64
X² 64 & X =√64 ==> X = 8
I'm pretty sure it's:
A right rectangular prism with length 15 inches, width of 8 inches, and height of 6 inches.
A cross section parallel to the base is a rectangle measuring 15 inches by 8 inches
A cross section perpendicular to the base through the midpoints of the 8-inch sides is a rectangle measuring 6 inches by 15 inches
Just visualize the rectangle
Answer:
(x, y) = (40, 30)
Step-by-step explanation:
A graphing calculator can show you the solution to this system of equations is (x, y) = (40, 30). That is the point of intersection where the two lines cross.
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An algebraic solution can be found by using the substitution method. An expression for y can be found using the second equation:
y = 110 -2x . . . . . . subtract 2x from both sides
Using this in the first equation gives ...
3x -4(110 -2x) = 0 . . . . substitute for y
11x = 440 . . . . . . . . . simplify, add 440
x = 40 . . . . . . . . . . divide by 11
y = 110 -2(40) = 30
The solution is (x, y) = (40, 30).